Embibe Experts Solutions for Chapter: Electrostatics, Exercise 12: Exercise (Analytical Questions)

Suppose the charge of a proton and an electron differ slightly. One of them is $-e,$ the other is $(e+\mathrm{\Delta }e).$ If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance $d$ (much greater than atomic size) apart is zero, then $\mathrm{\Delta }e$ is of the order of (Given mass of hydrogen, $m_h=1.67\times {10}^{-27} \mathrm{kg})$

An electron falls from rest through a vertical distance $h$ in a uniform and vertically upward directed electric field $E$. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance $h$. The time of fall of the electron, in comparison to the time of fall of the proton is 

If a charged spherical conductor of radius $10 \mathrm{cm}$ has potential $V$ at a point distant $5 \mathrm{cm}$ from its centre, then the potential at a point distant $15 \mathrm{cm}$ from the centre will be

Two charges $q_1$ and $q_2$ are placed $30\mathrm{cm}$ apart, as shown in the figure. A third charge $q$ is moved along the arc of a circle of radius $40\mathrm{cm}$ from $C$ to $D$. The change in the potential energy of the system is $\frac{{\mathrm{q}}_3}{4{\mathrm{\pi \epsilon }}_0}k$, where $k$ is:

Four points $a,b,c$ and $d$ are set at equal distance from the centre of a dipole as shown in the figure. The electrostatic potentials $V_a,V_b,V_c$ and $V_d$ would satisfy the following relation:

Figure shows a family of parallel equipotential surfaces and four paths along which an electron is made to move from one surface to another as shown.

(A) What is the direction of the electric field?

(B) Rank the paths according to work done, greatest first.

For the hollow thin cylinderical current carrying pipe which statement is correct :- 

If mechanical system is taken equivalent to electrical system then displacement $\left(x\right)$ is analogous to