Karen Morrison and Nick Hamshaw Solutions for Exercise 13: Exercise 15.13

A cuboid is $14 \mathrm{cm}$ long, $5 \mathrm{cm}$ wide and $3 \mathrm{cm}$ high. Calculate the length of its longest diagonal.(Give the answer in $\mathrm{cm}$ with two decimal places)

A cuboid is $14 \mathrm{cm}$ long, $5 \mathrm{cm}$ wide and $3 \mathrm{cm}$ high. Calculate the angle between the base and the longest diagonal.(Give the answer in degree measure with two decimal places)

$ABCD$ is a tetrahedral drinks carton. Triangle $ABC$ is the base and $B$ is a right angle. $D$ is vertically above $B$. And $AB=BC=6 \mathrm{cm}, BD=8 \mathrm{cm}$. Calculate length of $AC$.

$ABCD$ is a tetrahedral drinks carton. Triangle $ABC$ is the base and $B$ is a right angle. $D$ is vertically above $B$. And $AB=BC=6 \mathrm{cm}, BD=8 \mathrm{cm}$. Calculate length of $DA$.

$ABCD$ is a tetrahedral drinks carton. Triangle $ABC$ is the base and $B$ is a right angle. $D$ is vertically above $B$. And $AB=BC=6 \mathrm{cm}, BD=8 \mathrm{cm}$. Calculate length of $DC$.

$ABCD$ is a tetrahedral drinks carton. Triangle $ABC$ is the base and $B$ is a right angle. $D$ is vertically above $B$. And $AB=BC=6 \mathrm{cm}, BD=8 \mathrm{cm}$. Calculate size of the angle  $DAB$. (Give the answer in degree measure with two decimal places)

$ABCD$ is a tetrahedral drinks carton. Triangle $ABC$ is the base and $B$ is a right angle. $D$ is vertically above $B$. And $AB=BC=6 \mathrm{cm}, BD=8 \mathrm{cm}$. Calculate size of the angle  $BDC$. (Give the answer in degree measure with two decimal places)

$ABCD$ is a tetrahedral drinks carton. Triangle $ABC$ is the base and $B$ is a right angle. $D$ is vertically above $B$. And $AB=BC=6 \mathrm{cm}, BD=8 \mathrm{cm}$. Calculate size of the angle  $ADB$. (Give the answer in degree measure with two decimal places)