S P Singh Solutions for Chapter: Atomic Structure and Chemical Bonding, Exercise 4: EXERCISE 4(D)
S P Singh Chemistry Solutions for Exercise - S P Singh Solutions for Chapter: Atomic Structure and Chemical Bonding, Exercise 4: EXERCISE 4(D)
Attempt the practice questions on Chapter 4: Atomic Structure and Chemical Bonding, Exercise 4: EXERCISE 4(D) with hints and solutions to strengthen your understanding. Concise Chemistry Class 9 solutions are prepared by Experienced Embibe Experts.
Questions from S P Singh Solutions for Chapter: Atomic Structure and Chemical Bonding, Exercise 4: EXERCISE 4(D) with Hints & Solutions
Compare chlorine atom and chloride ion, with respect to their electrical state.
The electronic configuration of fluoride ion is the same as that of a neon atom. What is the difference between the two ?
What do you understand by the redox reactions?
Explain oxidation and reduction in terms of loss or gain of electrons.
Potassium (At. No. ) and chlorine (At. No. ) form a compound. Explain the formation of the compound on the basis of :
Oxidation.
Potassium (At. No. ) and chlorine (At. No. ) form a compound. Explain the formation of the compound on the basis of reduction.
Potassium (At. No. ) and chlorine (At. No. ) form a compound. Explain the formation of the compound on the basis of:
Oxidising agent.
Potassium (At. No. ) and chlorine (At. No. ) form a compound. Explain the formation of the compound on the basis of:
Reducing agent.
