Construct a cumulative frequency distribution table from the frequency table given below: Class Interval Frequency 1 - 10 12 11 - 20 18 21 - 30 23 31 - 40 15 41 - 50 10

We are given to construct a cumulative frequency distribution table from the frequency table given below: Class Interval Frequency 1 - 10 12 11 - 20 18 21 - 30 23 31 - 40 15 41 - 50 10 We know that the cumulative frequency of a class interval is the sum of frequencies of all classes up to that class (including the frequency of that particular class). In this case, we shall construct a less than type cumulative frequency distribution table that is given below: Class Interval Frequency Cumulative frequency Less than 10 12 12 Less than 20 18 30 Less than 30 23 53 Less than 40 15 68 Less than 50 10 78

Construct a frequency distribution table from the following cumulative frequency distribution: Class Interval Cumulative Frequency 10 - 19 8 20 - 29 19 30 - 39 23 40 - 49 30

We are given to construct a frequency distribution table from the following cumulative frequency distribution: Class Interval Cumulative Frequency 10 - 19 8 20 - 29 19 30 - 39 23 40 - 49 30 We know that the cumulative frequency of a class interval is the sum of frequencies of all classes up to that class (including the frequency of that particular class). Hence, the frequency of a class can be obtained by subtracting the cumulative frequency of the previous class from the cumulative frequency of the class. Hence, the frequency distribution table is as follows: Class Interval Cumulative Frequency Frequency 10 - 19 8 8 20 - 29 19 11 30 - 39 23 4 40 - 49 30 7

Construct a frequency distribution table from the following cumulative frequency distribution: Class Interval Cumulative Frequency 5 - 10 18 10 - 15 30 15 - 20 46 20 - 25 73 25 - 30 90

We are given to construct a frequency distribution table from the following cumulative frequency distribution: Class Interval Cumulative Frequency 5 - 10 18 10 - 15 30 15 - 20 46 20 - 25 73 25 - 30 90 We know that the cumulative frequency of a class interval is the sum of frequencies of all classes up to that class (including the frequency of that particular class). Hence, the frequency of a class can be obtained by subtracting the cumulative frequency of the previous class from the cumulative frequency of the class. Hence, the frequency distribution table is as follows: Class Interval Cumulative Frequency Frequency 5 - 10 18 18 10 - 15 30 12 15 - 20 46 16 20 - 25 73 27 25 - 30 90 17

Construct a frequency table from the following data: Marks Number of students Less than 10 6 Less than 20 15 Less than 30 30 Less than 40 39 Less than 50 53 Less than 60 70

We are given to construct a frequency table from the following data. Marks Number of students Less than 10 6 Less than 20 15 Less than 30 30 Less than 40 39 Less than 50 53 Less than 60 70 We observe that the 'marks' column has a class width of 10 . Hence, the classes will be 0 - 10 , 10 - 20 , 20 - 30 , . . . . . . . . etc. We also observe that the frequencies in the 'number of students' column are given in less than type cumulative frequency. We know that the cumulative frequency of a class interval is the sum of frequencies of all classes up to that class (including the frequency of that particular class). Hence, the frequency of a class can be obtained by subtracting the cumulative frequency of the previous class from the cumulative frequency of the class. Hence, the frequency distribution table is as follows: Marks Marks class Number of students (cumulative) Number of students Less than 10 0 - 10 6 6 Less than 20 10 - 20 15 9 Less than 30 20 - 30 30 15 Less than 40 30 - 40 39 9 Less than 50 40 - 50 53 14 Less than 60 50 - 60 70 17

Construct the frequency distribution table from the following cumulative frequency table: Ages Number of students Below 4 0 Below 7 85 Below 10 140 Below 13 243 Below 16 300 State the number of students in the age group 10 - 13 .

We are given to construct the frequency distribution table from the following cumulative frequency table and then find the number of students in the age group 10 - 13 . Ages Number of students Below 4 0 Below 7 85 Below 10 140 Below 13 243 Below 16 300 We observe that the 'marks' column has a class width of 3 . Hence, the classes will be 1 - 4 , 4 - 7 , 7 - 10 , 10 - 13 and 13 - 16 . We also observe that the frequencies in the 'number of students' column are given in less than type cumulative frequency. We know that the cumulative frequency of a class interval is the sum of frequencies of all classes up to that class (including the frequency of that particular class). Hence, the frequency of a class can be obtained by subtracting the cumulative frequency of the previous class from the cumulative frequency of the class. Hence, the frequency distribution table is as follows: Ages Age class Number of students (cumulative) Number of students Below 4 1 - 4 0 0 Below 7 4 - 7 85 85 Below 10 7 - 10 140 55 Below 13 10 - 13 243 103 Below 16 13 - 16 300 57 Clearly, the number of students in the age group 10 - 13 is 103 .

Construct the frequency distribution table from the following cumulative frequency table: Ages Number of students Below 4 0 Below 7 85 Below 10 140 Below 13 243 Below 16 300 State the age group which has the least number of students.

We are given to construct the frequency distribution table from the following cumulative frequency table and then find the age group that has the least number of students. Ages Number of students Below 4 0 Below 7 85 Below 10 140 Below 13 243 Below 16 300 We observe that the 'marks' column has a class width of 3 . Hence, the classes will be 1 - 4 , 4 - 7 , 7 - 10 , 10 - 13 and 13 - 16 . We also observe that the frequencies in the 'number of students' column are given in less than type cumulative frequency. We know that the cumulative frequency of a class interval is the sum of frequencies of all classes up to that class (including the frequency of that particular class). Hence, the frequency of a class can be obtained by subtracting the cumulative frequency of the previous class from the cumulative frequency of the class. Hence, the frequency distribution table is as follows: Ages Age class Number of students (cumulative) Number of students Below 4 1 - 4 0 0 Below 7 4 - 7 85 85 Below 10 7 - 10 140 55 Below 13 10 - 13 243 103 Below 16 13 - 16 300 57 Clearly, the age group that has the least number of students.number of students 0 is 1 - 4 .

R K Bansal Solutions for Exercise 1: EXERCISE

Author:R K Bansal

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Exercise 1: EXERCISE

Attempt the practice questions from Exercise 1: EXERCISE with hints and solutions to strengthen your understanding. Concise Mathematics I.C.S.E - Class IX solutions are prepared by Experienced Embibe Experts.

Questions from R K Bansal Solutions for Exercise 1: EXERCISE with Hints & Solutions

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 8

Construct a cumulative frequency distribution table from the frequency table given below:

Class Interval	Frequency
$1 - 10$	$12$
$11 - 20$	$18$
$21 - 30$	$23$
$31 - 40$	$15$
$41 - 50$	$10$

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 9

Construct a frequency distribution table from the following cumulative frequency distribution:

Class Interval	Cumulative Frequency
$10 - 19$	$8$
$20 - 29$	$19$
$30 - 39$	$23$
$40 - 49$	$30$

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 9

Construct a frequency distribution table from the following cumulative frequency distribution:

Class Interval	Cumulative Frequency
$5 - 10$	$18$
$10 - 15$	$30$
$15 - 20$	$46$
$20 - 25$	$73$
$25 - 30$	$90$

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 10

Construct a frequency table from the following data:

Marks	Number of students
Less than $10$	$6$
Less than $20$	$15$
Less than $30$	$30$
Less than $40$	$39$
Less than $50$	$53$
Less than $60$	$70$

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 11

Construct the frequency distribution table from the following cumulative frequency table:

Ages	Number of students
Below $4$	$0$
Below $7$	$85$
Below $10$	$140$
Below $13$	$243$
Below $16$	$300$

State the number of students in the age group $10 - 13$ .

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 11

Construct the frequency distribution table from the following cumulative frequency table:

Ages	Number of students
Below $4$	$0$
Below $7$	$85$
Below $10$	$140$
Below $13$	$243$
Below $16$	$300$

State the age group which has the least number of students.

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 13

The value of $π$ up to $50$ decimal places is $3 \cdot 14159265358979323846264338327950288419716939937510$

Make a frequency distribution table of the digits from $0$ to $9$ after the decimal place.

MEDIUM

9th ICSE

IMPORTANT

Concise Mathematics I.C.S.E - Class IX>Chapter 18 - Statistics>EXERCISE>Q 13

The value of $π$ up to $50$ decimal places is $3 \cdot 14159265358979323846264338327950288419716939937510$

Which are the most and the least occurring digits?

R K Bansal Solutions for Exercise 1: EXERCISE

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Exercise 1: EXERCISE

Questions from R K Bansal Solutions for Exercise 1: EXERCISE with Hints & Solutions

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