Factorise 6 2 3 2 - 2 1 3 2

Given, 6 2 3 2 - 2 1 3 2 ⇒ 20 3 2 - 7 3 2 By using an appropriate algebraic identity, we have, x 2 - y 2 = ( x + y ) ( x - y ) ⇒ 20 3 - 7 3 20 3 + 7 3 ⇒ 13 3 × 27 3 = 13 3 × 9 ⇒ 13 × 3 = 39 Hence, this is the required answer.

Factorise 7 3 10 2 - 2 1 10 2

Given, 7 3 10 2 - 2 1 10 2 We can write the given expressions like, 73 10 2 - 21 10 2 By using an appropriate algebraic identity, we have, x 2 - y 2 = ( x + y ) ( x - y ) = 73 10 - 21 10 73 10 + 21 10 ⇒ 52 10 × 94 10 = 26 5 × 47 5 = 48 22 25 Hence, this is the required answer.

E M B I B E

Concise Mathematics Middle School Class 8>Chapter 13 - Factorisation>EXERCISE 13(C)

R K Bansal Solutions for Chapter: Factorisation, Exercise 3: EXERCISE 13(C)

Author:R K Bansal

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Chapter: Factorisation, Exercise 3: EXERCISE 13(C)

Attempt the free practice questions on Chapter 13: Factorisation, Exercise 3: EXERCISE 13(C) with hints and solutions to strengthen your understanding. Concise Mathematics Middle School Class 8 solutions are prepared by Experienced Embibe Experts.