Find the median of the following data: Class 4 - 8 8 - 12 12 - 16 16 - 20 20 - 24 24 - 28 Frequency 9 16 12 7 15 1

We have to find the median of the following data: Class 4 - 8 8 - 12 12 - 16 16 - 20 20 - 24 24 - 28 Frequency 9 16 12 7 15 1 Cumulative frequency(c.f.) 9 9 + 16 = 25 25 + 12 = 37 37 + 7 = 44 44 + 15 = 59 59 + 1 = 60 Here n = 60 ⇒ 2 n = 30 Cumulative frequency greater than 30 is 37 and the class corresponding to it is 12 − 16 &there4; Class 12 − 16 is the median class &there4; Lower limit ( l ) = 12 , 2 n = 30 , c . f . = 25 , f = 12 and h = 4 Substituting the values, we get M = l + ( 2 n − c . f . ) f × h M = 12 + 30 − 25 12 × 4 = 12 + 5 3 = 12 + 1 . 67 = 13 . 67 Hence, Median is 13 . 67 .

Find the mode of the following data Class 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80 - 90 90 - 100 Frequency 12 17 28 23 7 8 5

We have to find the mode of the following data Class 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80 - 90 90 - 100 Frequency 12 17 28 23 7 8 5 Modal class is 50 - 60 as it has the highest frequency. l 1 = 50 f o = 17 f 1 = 28 f 2 = 23 c = 10 Mode = l 1 + f 1 − f o 2 f 1 − f o − f 2 × c = 50 + 11 56 - 17 - 23 × 10 = 50 + 11 16 × 10 = 50 + 6 . 875 = 56 . 875

Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Gujarat Board-2019

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Embibe Experts Mathematics Solutions for Exercise - Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Gujarat Board-2019

Attempt the free practice questions on Chapter 14: Statistics, Exercise 1: Gujarat Board-2019 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Gujarat Board-2019 with Hints & Solutions

EASY

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2018>Q 2

Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
Frequency	$7$	$15$	$13$	$17$	$10$

The cumulative frequency of the class $20 - 30$ of the above frequency distribution is _____.

EASY

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2018>Q 3

Ogive is graphical representation of _____ in a frequency distribution.

EASY

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2019>Q 11

Find the median of the following data:

Class	$4 - 8$	$8 - 12$	$12 - 16$	$16 - 20$	$20 - 24$	$24 - 28$
Frequency	$9$	$16$	$12$	$7$	$15$	$1$

EASY

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2019>Q 12

Find the mode of the following data

Class	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$	$70 - 80$	$80 - 90$	$90 - 100$
Frequency	$12$	$17$	$28$	$23$	$7$	$8$	$5$

MEDIUM

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2020>Q 14

Find the median of the data from the above graph.

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MEDIUM

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2020>Q 15

State the type for curve A and curve $B$

Question Image

HARD

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2020>Q 16

The following frequency distribution gives the monthly consumption of electricity of $68$ consumers of a locality. The median of the given frequency distribution is $137$ units. Find the number of consumers whose monthly consumption is between $105 - 125$ and also for $145 - 165$ .

Monthly consumption in units	$65 - 85$	$85 - 105$	$105 - 125$	$125 - 145$	$145 - 165$	$165 - 185$	$185 - 205$
Number of consumers	$04$	$05$	$-$	$20$	$-$	$08$	$04$

HARD

10th Gujarat Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Statistics>Gujarat Board-2020>Q 17

Lifetime(In Hours)	$0 - 200$	$200 - 400$	$400 - 600$	$600 - 800$	$800 - 1000$	$1000 - 1200$
Frequency	$9$	$35$	$50$	$61$	$38$	$32$

The above data gives the information on the observed lifetimes (in hours) of $225$ electrical components. Find the mean.

Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Gujarat Board-2019

Embibe Experts Mathematics Solutions for Exercise - Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Gujarat Board-2019

Questions from Embibe Experts Solutions for Chapter: Statistics, Exercise 1: Gujarat Board-2019 with Hints & Solutions

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