The radius of the innermost electron orbit of hydrogen atom is 5 . 3 × 10 - 11 m . What are the radii of n = 2 and n = 3 orbits ?

The innermost orbit’s radius of a hydrogen atom, r 1 = 5 . 3 × 10 - 11 m Let r 2 be the radius of the orbit at n = 2 It is related to the radius of the innermost orbit as: r 2 = ( n ) 2 r 1 = 4 × 5 . 3 × 10 - 11 = 2 . 12 × 10 - 10 m For n = 3 , the respective orbit radius can be written as: r 3 = ( n ) 2 r 1 = 9 × 5 . 3 × 10 - 11 = 4 . 77 × 10 - 10 m The electronic orbit radius for ( n = 2 ) is 2 . 12 × 10 - 10 m and for ( n = 3 ) is 4 . 77 × 10 - 10 m .

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 12 - Atoms>Meghalaya-2020

Embibe Experts Solutions for Chapter: Atoms, Exercise 1: Meghalaya-2018

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Atoms, Exercise 1: Meghalaya-2018

Attempt the free practice questions on Chapter 12: Atoms, Exercise 1: Meghalaya-2018 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS solutions are prepared by Experienced Embibe Experts.