Embibe Experts Solutions for Chapter: Laws of Motion, Exercise 1: MHT-CET Medical 2020

Work done in sliding a $1 \mathrm{kg}$ block up a rough inclined plane of height $5 \mathrm{m}$ is $100 \mathrm{J}.$ Work done against the friction is $\left(\mathrm{g}=10 \mathrm{m}/{\mathrm{s}}^2\right)$:

A body of mass $m$ is suspended from the rigid support by an inextensible string of length $L$ on which another identical body of mass $m$ struck inelastically moving with horizontal velocity $\sqrt{2gL}$. The increase in the tension just after it is struck by the body is ($g=$ acceleration due to gravity)

Two masses $m_1$ and $m_2$ moving with velocities $v_1$ and $v_2$ in opposite directions collide elastically and after collision $m_1$ and $m_2$ move with velocity $v_2$ and $v_1$ respectively. the ratio $v_2/v_1$ is