Embibe Experts Solutions for Exercise 6: EXERCISE

A potentiometer consists of a wire of length $4 \mathrm{m}$ and resistance $10 \mathrm{\Omega }$. It is connected to a cell of e.m.f. $2 \mathrm{V}$. The potential difference per unit length of the wire will be 

A galvanometer gives full scale deflection with $0.2 \mathrm{A}$ in its coil. The resistance of its coil is $10 \mathrm{\Omega }.$. How much shunt resistance is required to convert it into an ammeter to read current up to $1.8 \mathrm{A} ?$

In a potentiometer experiment, two primary cells are connected in series to support each other and then connected to oppose each other. The balance points are obtained at $4 \mathrm{m}$ and $1 \mathrm{m}$ respectively. The ratio of electromotive forces of the two cells is

For a cell of emf $2 \mathrm{V}$, a balance point is obtained for $50 \mathrm{cm}$ of the potentiometer wire. If the cell is shunted by a $2 \mathrm{\Omega }$ resistor, the balance is obtained across $40 \mathrm{cm}$ of the wire, then the internal resistance of the cell is

A galvanometer of resistance $2\mathrm{\Omega }$ and having full scale deflection for a current of $100 \mathrm{mA}$ can be converted into a volt meter of range $5$ Volt by connecting a resistance $R$ in series with galvanometer. The resistance $\text{'}R\text{'}$ is

Voltmeters $V_1$ and $V_2$ are connected in series across a DC line. $V_1$ reads $80 \mathrm{V}$ and has a $\mathrm{per} \mathrm{volt}$ resistance of $200 \mathrm{\Omega }$. $V_2$ has a total resistance of $32 \mathrm{k\Omega }$. The line voltage is