Embibe Experts Solutions for Exercise 1: EXERCISE

$\sqrt{-5}\sqrt{-\frac{16}{5}}=$

If $\left(x+iy\right)\left(p+iq\right)=\left(x^2+y^2\right)i,$ then, where $x, y, p, q\in R$

$\left|\left(1+i\right)\frac{(2+i)}{(3+i)}\right|$ equals

$a+ib>c+id$ is meaningful only when

The polar form of complex number $\frac{i-1}{\cos \frac{\pi }{3}+i\sin \frac{\pi }{3}}$ is given by

If $a^2+b^2=1,$ then $\frac{1+b+ia}{1+b-ia}$ is equal to, (where $a, b\in R).$

If $z=3-4i,$ then $z^4-3z^3+3z^2+99z-95$ is equal to

If $z=x-iy$ and $z^{\frac{1}{3}}=p+iq,$ then $\frac{\left(\frac{x}{p}+\frac{y}{q}\right)}{p^2+q^2}$ is equal to, where $x, y, p, q\in R$