Embibe Experts Solutions for Exercise 4: EXERCISE 2.4

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Exercise 4: EXERCISE 2.4

Attempt the practice questions from Exercise 4: EXERCISE 2.4 with hints and solutions to strengthen your understanding. Gamma Question Bank for Engineering Physics solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Exercise 4: EXERCISE 2.4 with Hints & Solutions

EASY
JEE Main/Advance
IMPORTANT

Consider a hollow spherical conductor that has a potential of 300 volts at its outside surface. The potential inside the hollow must be

EASY
JEE Main/Advance
IMPORTANT

Two copper spheres of same radii (one hollow and other solid) are charged to the same potential then

EASY
JEE Main/Advance
IMPORTANT

A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 V. The potential at a distance of 2 cm from the centre of the sphere is

MEDIUM
JEE Main/Advance
IMPORTANT

Electric field and potential inside hollow charged conducting sphere are respectively (q= charge on sphere, R= Radius of sphere, r= distance from centre of sphere)

HARD
JEE Main/Advance
IMPORTANT

Two insulated charged conducting spheres of radii 20 cm and 15 cm, respectively and having an equal charge of 10 μC are connected by a copper wire and then, they are separated. Then,

EASY
JEE Main/Advance
IMPORTANT

A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer of hollow shell be V. If the shell is now given a charge of -3Q, the new potential difference between the same two surface is,

MEDIUM
JEE Main/Advance
IMPORTANT

In a uniform electric field E=100 V m-1, the potential difference VA-VB, where AB=102 m, is

Question Image

HARD
JEE Main/Advance
IMPORTANT

A soap bubble of radius 3 cm is charged with 9.0 nC. The excess pressure inside the bubble, if surface tension of soap solution =3×10-3 N m-1 is