Embibe Experts Solutions for Exercise 1: EXERCISE

The equation of an alternating voltage is $V=220\sin \left[\omega t+\frac{\pi }{6}\right]$ and the equation for current is $I=10\sin \left(\omega t+\frac{\pi }{6}\right).$ The impedance (in ohm) of the circuit is

Impedance of the circuit shown in the figure is

If resistance $R=10 \mathrm{\Omega },$ inductance $L=2 \mathrm{mH}$ and capacitance $C=5\mu \mathrm{F}$ are connected in series to an $AC$ source of frequency $50 \mathrm{Hz},$ then at resonance the impedance of circuit is

In the circuit shown in figure the current measured by ammeter is

If reading of voltmeter $V$ shown in the figure at resonance is $200 \mathrm{V},$ then the quality factor of the circuit is

A capacitor of capacitance $1\mu F$ is charged to a potential of $1 \mathrm{V}.$ It is connected in parallel to an inductor of inductance ${10}^{-3}\mathrm{H}.$ The maximum current that will flow in the circuit has the value

If power factor is $\frac{1}{2}$ in a series $RL$ circuit. $R=100 \mathrm{\Omega },$ then $L$ is $(f=50 \mathrm{Hz})$

An ideal transformer has $100$ turns in the primary and $250$ turns in the secondary. The peak value of the ac is $28 \mathrm{V}.$ The r.m.s. secondary voltage is nearest to