Assignment

Value of the resistance $R$ in the figure is

Current through the $25 \mathrm{\Omega }$ resistor as shown in figure is

Two cells of emf $E_1$ and $E_2\left(E_1>E_2\right)$ are connected individually to a potentiometer and their corresponding balancing length are $625 \mathrm{cm}$ and $500 \mathrm{cm},$ then the ratio $\frac{E_1}{E_2}$ is

Five cells each of emf $E$ and internal resistance $r$ are connected in series. Due to oversight one cell is connected wrongly. The equivalent internal resistance of the combination is

In the following diagram, the lengths of wires $AB$ and $BC$ are equal but the radius of wire $AB$ is double to that of $BC.$ The ratio of potential gradient on wires $AB$ and on $BC$ will be (wires are made of same material)

Three identical bulbs are connected as shown in figure. When switch $S$ is closed, the power consumed in bulb $B$ is $P.$ What will be the power consumed by the same bulb when switch $S$ is opened?

Two identical bulbs are connected in parallel across an ideal source of emf $E.$ The ammeter $A$ and voltmeter $V$ are ideal. If bulb $B_2$ gets fused, then

Ten $60 \mathrm{W}, 220 \mathrm{V}$ bulbs are connected in series to $220 \mathrm{V}$ supply. Power consumed in the circuit is