Rationalize the denominator: 3 4 2

Given expression: 3 4 2 The rationalizing factor of 4 2 is 2 . We multiply the numerator and denominator by 2 . Hence, 3 4 2 = 3 × 2 4 2 × 2 = 3 2 4 × 2 × 2 = 3 2 4 × 4 = 3 2 4 × 2 = 3 2 8

Rationalize the denominator: 2 5 3

Given expression: 2 5 3 The rationalizing factor of 5 3 is 3 . We multiply the numerator and denominator by 3 . Hence, 2 5 3 = 2 × 3 5 3 × 3 = 2 3 5 3 × 3 = 2 3 5 9 = 2 3 5 × 3 = 2 3 15 Hence, the required answer is 2 3 15 .

Rationalize the denominator: 7 2 5 .

Given expression: 7 2 5 The rationalizing factor of 2 5 is 5 . We multiply the numerator and denominator by 5 . Hence, 7 2 5 = 7 × 5 2 5 × 5 = 7 5 2 5 × 5 = 7 5 2 25 = 7 5 2 × 5 = 7 5 10 Hence, the required answer is 7 5 10 .

Rationalize the denominator: 5 3 7

Given expression: 5 3 7 The rationalizing factor of 3 7 is 7 . We multiply the numerator and denominator by 7 . So, 5 3 7 = 5 × 7 3 7 × 7 = 5 7 3 × 7 × 7 = 5 7 3 × 49 = 5 7 3 × 7 = 5 7 21 Hence, the required answer is 5 7 21 .

Write 3 irrational numbers between. 15 and 20

Given numbers are 15 and 20 . Let us find the squares of the given numbers. 15 = 15 2 = 15 , 20 = 20 2 = 20 We need 3 numbers whose squares are between 15 and 20 . We can take the numbers 17 , 18 , and 19 . We know that 20 > 19 > 18 > 17 > 15 So, 20 > 19 > 18 > 17 > 15 The required numbers are 19 , 18 , 17 .

E M B I B E

ICSE Skills In Mathematics>Numbers>Chapter 4 - Decimals, Rationals and Irrationals>EXERCISE 4(B)

V K Raman and S N Sharma Solutions for Exercise 2: EXERCISE 4(B)

Author:V K Raman & S N Sharma

V K Raman Mathematics Solutions for Exercise - V K Raman and S N Sharma Solutions for Exercise 2: EXERCISE 4(B)

Attempt the practice questions from Exercise 2: EXERCISE 4(B) with hints and solutions to strengthen your understanding. ICSE Skills In Mathematics solutions are prepared by Experienced Embibe Experts.