V K Raman and S N Sharma Solutions for Exercise 5: CONCEPT REVISION TEST-16

$x^2-2=(x+1)(x-1)$

$a\left(x+1\right)-1\left(x+1\right)=\left(x+1\right)\left(a-1\right)$

$x^2-x+1$ can't be factorised.

$4a^2{b}^2-1=(2ab+1)(2ab-1)$

Factorising by grouping can be done only if the expression has an even number of terms

Factorize: $x^2-3x+2$.

Factorise: $2x^2+29x+50$.

Factorise: $a^2{b}^2-4ab+3$