V K Raman and S N Sharma Solutions for Exercise 1: EXERCISE

In the figure, find

$\angle B, \angle C$ and $\angle D$

$\mathrm{ABCD}$ is a rhombus. $\mathrm{AO}=2 \mathrm{cm}$, $\mathrm{BO}=4 \mathrm{cm}$, $\mathrm{AD}=5 \mathrm{cm}$, $\angle \mathrm{OAD}=63°$. Find the sides $\mathrm{OC}, \mathrm{OD}$ and angles of $△\mathrm{COD}$.

$\mathrm{ABC}$ is a $△$ in which $\mathrm{AB}=\mathrm{AC}, \angle \mathrm{A}=38°$ and $\mathrm{DE}\parallel \mathrm{BC}$. If $\mathrm{BD}=2.4 \mathrm{cm}$, If $\mathrm{CE}$ is $x \mathrm{cm}$, then find the value of $x$.

$\mathrm{ABC}$ is a $△$ in which $\mathrm{AB}=\mathrm{AC}, \angle \mathrm{A}=38°$ and $\mathrm{DE}\parallel \mathrm{BC}$. If $\mathrm{BD}=2.4 \mathrm{cm}$, find $\angle \mathrm{C}$.

$\mathrm{ABC}$ is a $△$ in which $\mathrm{AB}=\mathrm{AC}, \angle \mathrm{A}=38°$ and $\mathrm{DE}\parallel \mathrm{BC}$. If $\mathrm{BD}=2.4 \mathrm{cm}$, find $\angle \mathrm{BDE}$.

One angle of a parallelogram is five times the adjacent angle. Find the angles of the parallelogram.

$\mathrm{ABCD}$ is a parallelogram. $\mathrm{BO}, \mathrm{CO}$ are the bisectors of $\angle B, \angle C$ respectively. Given that $\angle \mathrm{BCO}=60°$ find:

$\angle \mathrm{OBC}$

$\mathrm{ABCD}$ is a parallelogram. $\mathrm{BO}, \mathrm{CO}$ are the bisectors of $\angle B, \angle C$ respectively. Given that $\angle \mathrm{BCO}=60°$ find:

$\angle \mathrm{BOC}$