Balance the following equation: XeF 6 + H 2 O → XeO 2 F 2 + HF

Given, equation is XeF 6 + H 2 O → XeO 2 F 2 + HF First balance the fluorine atoms on both sides of the equation followed by oxygen and hydrogen atoms. The balanced chemical equation is: XeF 6 + 2 H 2 O → XeO 2 F 2 + 4 HF Note: XeF 6 is a powerful fluorinating agent. They are readily hydrolysed even by traces of water. It also sublimes readily at 298 K .

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Intermediate Second Year Chemistry>Chapter 6 - p-Block Elements>Intext Questions

Telangana Board Solutions for Chapter: p-Block Elements, Exercise 16: Intext Questions

Author:Telangana Board

Telangana Board Chemistry Solutions for Exercise - Telangana Board Solutions for Chapter: p-Block Elements, Exercise 16: Intext Questions

Attempt the practice questions on Chapter 6: p-Block Elements, Exercise 16: Intext Questions with hints and solutions to strengthen your understanding. Intermediate Second Year Chemistry solutions are prepared by Experienced Embibe Experts.