Factorise, 64 a + b 2 - 49 x + y 2

Given, 64 a + b 2 - 49 x + y 2 and we have to factorise this expression. The given equation can be expressed as a 2 - b 2 Therefore, 64 a + b 2 - 49 x + y 2 = 8 a + b 2 - 7 x + y 2 Using the standard identity, a 2 - b 2 = a + b a - b , we will get, = 8 a + b + 7 x + y 8 a + b - 7 x + y Hence, the factors are 8 a + b + 7 x + y 8 a + b - 7 x + y .

Factorise: 1 0.09 a 2 - 0.0081 b 2

We need to factorise the expression 1 0.09 a 2 - 0.0081 b 2 The given equation can be expressed in the form a 2 - b 2 . Therefore, 1 0.09 a 2 - 0.0081 b 2 = 1 0.3 a 2 - 0.09 b 2 Using the standard identity, a 2 - b 2 = a + b a - b , we will get, = 1 0.3 a + 0.09 b 1 0.3 a - 0.09 b Hence, the factors are 1 0.3 a + 0.09 b 1 0.3 a - 0.09 b .

We need to factorise the expression x 4 - y 2 The given equation can be expressed in the form of a 2 - b 2 , Therefore, x 4 - y 2 = x 2 2 - y 2 Using the standard identity, a 2 - b 2 = ( a - b ) ( a + b ) , we will get, = ( x 2 + y ) ( x 2 - y ) Hence, the required factors are ( x 2 + y ) ( x 2 - y ) .

E M B I B E

Joy Of Mathematics 8>Chapter 13 - Factorisation>Revision Time

S.N. Chhibber Solutions for Chapter: Factorisation, Exercise 7: Revision Time

Author:S.N. Chhibber

S.N. Chhibber Mathematics Solutions for Exercise - S.N. Chhibber Solutions for Chapter: Factorisation, Exercise 7: Revision Time

Attempt the practice questions on Chapter 13: Factorisation, Exercise 7: Revision Time with hints and solutions to strengthen your understanding. Joy Of Mathematics 8 solutions are prepared by Experienced Embibe Experts.