Construct a histogram of the following frequency distribution: Number of babies 0 1 2 Number of families 20 80 60

Given: Number of babies 0 1 2 Number of families 20 80 60 A histogram is a graphical display of data using bars of different heights. Expressing the above data in the form of continuous frequency distribution, Number of babies - 0 . 5 - 0 . 5 0 . 5 - 1 . 5 1 . 5 - 2 . 5 Number of families 20 80 60 Hence, the frequency polygon is,

The frequency distribution of 11 teachers of the Bidyasagar primary school in the Birshingha village are as follows: Age(in years) 37 - 43 43 - 49 49 - 55 Number of teachers 02 05 04 Construct a histogram of the above frequency distribution.

Given: Age(in years) 37 - 43 43 - 49 49 - 55 Number of teachers 02 05 04 A histogram is a graphical display of data using bars of different heights. In a histogram, each bar groups numbers into ranges. Taller bars show that more data falls in that range. A histogram displays the shape and spread of continuous sample data. Hence, the histogram is

The frequency distribution of the number of goals of the teams of the Kolkata league are given below: Number of goals 1 2 3 4 Frequencies 20 12 8 6 Construct a frequency polygon of the above data.

Given: Number of goals 1 2 3 4 Frequencies 20 12 8 6 A frequency polygon is a graph constructed by using lines to join the midpoints of each interval, or bin. Expressing the above data in the form of continuous frequency distribution, Number of goals 0 . 5 - 1 . 5 1 . 5 - 2 . 5 2 . 5 - 3 . 5 3 . 5 - 4 . 5 Frequencies 20 12 8 6 Hence, the frequency polygon is

Construct a frequency polygon of the following frequency distribution: Class intervals 1 - 10 11 - 20 21 - 30 Frequencies 8 3 6

Convert the given frequency distribution into a continuous grouped frequency distribution: Consider the classes 1 - 10 and 11 - 20 . The lower limit of 1 - 10 = 10 The upper limit of 11 - 20 = 11 The difference = 11 - 10 = 1 Half the difference = 1 2 = 0 . 5 So, the new class interval formed from 1 - 10 is 1 - 0 . 5 - 10 + 0 . 5 i.e., 0 . 5 - 10 . 5 Continuous classes formed are: Class intervals 0 . 5 - 10 . 5 10 . 5 - 20 . 5 20 . 5 - 30 . 5 Frequencies 8 3 6 Hence, the frequency polygon is as follows

The marks obtained by 40 students in an examination of 100 marks are given below. Marks obtained 40 - 60 60 - 80 80 - 100 Number of students 10 20 10 Construct at first histogram and then frequency polygon in the same sheet.

Given: Marks obtained 40 - 60 60 - 80 80 - 100 Number of students 10 20 10 A frequency polygon is a graph constructed by using lines to join the midpoints of each interval or bin of the histogram. Hence, the histogram and frequency polygon is as follows,

The table of distributing the students into two sections, section- A and section- B according to their obtained marks of the Barasat govt. girl's school is as follows: Section- A Obtained marks Frequency 0 - 10 3 10 - 20 9 20 - 30 17 30 - 40 12 40 - 50 9 Section- B Marks obtained Frequency 0 - 10 5 10 - 20 19 20 - 30 15 30 - 40 16 40 - 50 1 Construct two frequency polygons for two sections in the same graph paper.

A frequency polygon is a graph constructed by using lines to join the midpoints of each interval, or bin. We know that, Class mark = Upper limit + Lower limit 2 First we obtain the class marks as given in the following table: Obtained marks Class marks Frequency of section- A Frequency of section- B 0 - 10 5 3 5 10 - 20 15 9 19 20 - 30 25 17 15 30 - 40 35 12 16 40 - 50 45 9 1 Hence, frequency polygon is as follows:

The frequency distribution of the ages of the babies playing in the park of college square are given in the following table: Ages(in year) 0 - 2 2 - 4 4 - 6 6 - 8 Number of babies 4 6 8 2 Construct a histogram and then frequency polygon in the same sheet.

A histogram is a graphical display of data using bars of different heights. A frequency polygon is a graph constructed by using lines to join the midpoints of each interval, or bin. A frequency polygon can be created from the histogram or by calculating the midpoints of the bins from the frequency distribution table. Hence, the graph is as follows:

The frequency distribution of the marks above 60 % obtained in an examination of testing the skill in mathematics of 1000 students of Russia, India, China and America, dividing them into two age groups, are given below: Country Number of students of age group 10 - 15 Number of students of age group 15 - 20 Russia 400 500 India 300 400 China 400 300 America 300 300 Construct 4 frequency polygons for four countries in the same graph paper taking same axes and origin.

A frequency polygon is a graph constructed by using lines to join the midpoints of each interval, or bin. We know that, Class mark = Upper limit + Lower limit 2 First we obtain the class marks as given in the following table: Age group Class marks Russia India China America 10 - 15 12 . 5 400 300 400 300 15 - 20 17 . 5 500 400 300 300 Hence, the graph is as follows

Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-2

Author:Kesab Chandra Nag

Kesab Chandra Nag Mathematics Solutions for Exercise - Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-2

Attempt the practice questions from Exercise 1: EXERCISE-2 with hints and solutions to strengthen your understanding. MATHEMATICS CLASS 9 solutions are prepared by Experienced Embibe Experts.

Questions from Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-2 with Hints & Solutions

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

Construct a histogram of the following frequency distribution:

Number of babies	$0$	$1$	$2$
Number of families	$20$	$80$	$60$

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

The frequency distribution of $11$ teachers of the Bidyasagar primary school in the Birshingha village are as follows:

Age(in years)	$37 - 43$	$43 - 49$	$49 - 55$
Number of teachers	$02$	$05$	$04$

Construct a histogram of the above frequency distribution.

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

The frequency distribution of the number of goals of the teams of the Kolkata league are given below:

Number of goals	$1$	$2$	$3$	$4$
Frequencies	$20$	$12$	$8$	$6$

Construct a frequency polygon of the above data.

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

Construct a frequency polygon of the following frequency distribution:

Class intervals	$1 - 10$	$11 - 20$	$21 - 30$
Frequencies	$8$	$3$	$6$

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

The marks obtained by $40$ students in an examination of $100$ marks are given below.

Marks obtained	$40 - 60$	$60 - 80$	$80 - 100$
Number of students	$10$	$20$	$10$

Construct at first histogram and then frequency polygon in the same sheet.

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

The table of distributing the students into two sections, section- $A$ and section- $B$ according to their obtained marks of the Barasat govt. girl's school is as follows:

Section- $A$

Obtained marks	Frequency
$0 - 10$	$3$
$10 - 20$	$9$
$20 - 30$	$17$
$30 - 40$	$12$
$40 - 50$	$9$

Section- $B$

Marks obtained	Frequency
$0 - 10$	$5$
$10 - 20$	$19$
$20 - 30$	$15$
$30 - 40$	$16$
$40 - 50$	$1$

Construct two frequency polygons for two sections in the same graph paper.

EASY

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

The frequency distribution of the ages of the babies playing in the park of college square are given in the following table:

Ages(in year)	$0 - 2$	$2 - 4$	$4 - 6$	$6 - 8$
Number of babies	$4$	$6$	$8$	$2$

Construct a histogram and then frequency polygon in the same sheet.

MEDIUM

9th West Bengal Board

IMPORTANT

MATHEMATICS CLASS 9>Chapter 23 - Histogram and Frequency Polygon>EXERCISE-2>Q 3

The frequency distribution of the marks above $60 %$ obtained in an examination of testing the skill in mathematics of $1000$ students of Russia, India, China and America, dividing them into two age groups, are given below:

Country	Number of students of age group $10 - 15$	Number of students of age group $15 - 20$
Russia	$400$	$500$
India	$300$	$400$
China	$400$	$300$
America	$300$	$300$

Construct $4$ frequency polygons for four countries in the same graph paper taking same axes and origin.

Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-2

Kesab Chandra Nag Mathematics Solutions for Exercise - Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-2

Questions from Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-2 with Hints & Solutions

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