Solve: 5 x 5 y = 25 , 4 y 2 x = 2

Given, 5 x 5 y = 25 , 4 y 2 x = 2 Now, 5 x 5 y = 25 ⇒ 5 x = 25 × 5 y ⇒ 5 x = 5 2 × 5 y ⇒ x = 2 + y . . . . . . . . . ( i ) And 4 y 2 x = 2 . . . . . . ( i i ) Put the value of x ⇒ 4 y 2 2 + y = 2 ⇒ 2 2 y 2 2 + y = 2 ⇒ 2 2 y - 2 - y = 2 ⇒ y - 2 = 1 ⇒ y = 3 Put the value of y in equation ( i ) ⇒ x = 2 + y ⇒ x = 2 + 3 ⇒ x = 5 Thus, the value of x = 5 , y = 3

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MATHEMATICS CLASS 9>Algebra>Chapter 8 - Laws of Indices>EXERCISE-6

Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-6

Author:Kesab Chandra Nag

Kesab Chandra Nag Mathematics Solutions for Exercise - Kesab Chandra Nag Solutions for Exercise 1: EXERCISE-6

Attempt the practice questions from Exercise 1: EXERCISE-6 with hints and solutions to strengthen your understanding. MATHEMATICS CLASS 9 solutions are prepared by Experienced Embibe Experts.