R. D. Sharma Solutions for Chapter: Pair of Linear Equations in Two Variables, Exercise 9: EXERCISE 3.9

The present age of a father is three years more than three times the age of the son. Three years hence father's age will be $10$ years more than twice the age of the son. Determine their present ages.

A father is three times as old as his son. In $12$ years time, he will be twice as old as his son. Find the present ages of the father and the son.

Father's age is three times the sum of age of his two children. After $5$ years his age will be twice the sum of ages of two children. Find the age of father.

Two years ago, a father was five times as old as his son. Two years later, his age will be $8$ more than three times the age of his son. Find the present ages of father and son.

$A$ is elder to $B$ by $2$ years. $A$'s father $F$ is twice as old as $A$ and $B$ is twice as old as his sister $S$. If the ages of the father and sister differ by $40$ years, find the age of $A$.

The ages of two friends Ani and Biju differ by $3$ years. Ani's father Dharma is twice as old as Ani and Biju as twice as old as his sister Cathy. The ages of Cathy and Dharam differ by $30$ years. Find the ages of Ani and Biju.

Two years ago, Salim was thrice as old as his daughter and six years later, he will be four years older than twice her age. How old are they now?

The age of the father is twice the sum of the ages of his two children. After $20$ years, his age will be equal to the sum of the ages of his children. Find the age of the father.