R S Aggarwal Solutions for Chapter: Mensuration, Exercise 7: EXERCISE 20G

The ratio of the area of a square of side $a$ and that of an equilateral triangle of side $a$ is:

The area of a square is equal to the area of a circle. What is the ratio between the side of the square and the radius of the circle?

Each side of an equilateral triangle is equal to the radius of a circle whose area is $154 {\mathrm{cm}}^2$. The area of the triangle is:

The area of a rhombus is $36 {\mathrm{cm}}^2$ and the length of one of its diagonals is $6 \mathrm{cm}$. The length of the second diagonal is:

The area of a rhombus is $144 {\mathrm{cm}}^2$ and one of its diagonals is double the other. The length of the longer diagonal is:

The area of a circle is $24.64 {\mathrm{m}}^2$. The circumference of the circle is:

[Take $\mathrm{\pi }=\frac{22}{7}$]

The area of a circle is increased by $22 {\mathrm{cm}}^2$ when its radius is increased by $1 \mathrm{cm}$. The original radius of the circle is

The radius of a circular wheel is $1.75 \mathrm{m}$. How many revolutions will it make in travelling $11 \mathrm{km}$?