Find the perimeter of the following rectangle. Length of the rectangle Breadth of the rectangle Perimeter by adding all sides Perimeter by 2 × ( length + breadth ) 0 . 5 m 0 . 25 m

Given, Length of the rectangle = 0 . 5 m Breadth of the rectangle = 0 . 25 m The perimeter can be defined as the boundary that surrounds a shape. We can find the perimeter of a rectangle by adding all the sides of it or using the formula of the perimeter. Sum of all sides = length + length + breadth + breadth = perimeter Thus, perimeter = 0 . 5 m + 0 . 5 m + 0 . 25 m + 0 . 25 m = 1 . 50 m The formula of the perimeter of a rectangle is = 2 × ( length + breadth ) Therefore, Perimeter = 2 × ( 0 . 5 + 0 . 25 ) m = 1 . 50 m

Find the perimeter of the following rectangle. Length of the rectangle Breadth of the rectangle Perimeter by adding all sides Perimeter by 2 × ( length + breadth ) 18 cm 15 cm

Given, Length of the rectangle = 18 cm Breadth of the rectangle = 15 cm The perimeter can be defined as the boundary that surrounds a shape. We can find the perimeter of a rectangle by adding all the sides of it or using the formula of the perimeter. Sum of all sides = length + length + breadth + breadth = perimeter Thus, perimeter = 18 cm + 18 cm + 15 cm + 15 cm = 66 cm The formula of the perimeter of a rectangle is = 2 × ( length + breadth ) Therefore, Perimeter = 2 × ( 18 + 15 ) cm = 66 cm

Find the perimeter of the following rectangle. Length of the rectangle Breadth of the rectangle Perimeter by adding all sides Perimeter by 2 × ( length + breadth ) 10 . 5 cm 8 . 5 cm

Given, Length of the rectangle = 10 . 5 cm Breadth of the rectangle = 8 . 5 cm The perimeter can be defined as the boundary that surrounds a shape. We can find the perimeter of a rectangle by adding all the sides of it or using the formula of the perimeter. Sum of all sides = length + length + breadth + breadth = perimeter Thus, perimeter = 10 . 5 cm + 10 . 5 cm + 8 . 5 cm + 8 . 5 cm = 38 cm The formula of the perimeter of a rectangle is = 2 × ( length + breadth ) Therefore, Perimeter = 2 × ( 10 . 5 + 8 . 5 ) cm = 38 cm

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MERRY MATH - 6>Chapter 10 - Mensuration>Try These

Jammu and Kashmir Board Solutions for Chapter: Mensuration, Exercise 1: Try These

Author:Jammu and Kashmir Board

Jammu and Kashmir Board Mathematics Solutions for Exercise - Jammu and Kashmir Board Solutions for Chapter: Mensuration, Exercise 1: Try These

Attempt the practice questions on Chapter 10: Mensuration, Exercise 1: Try These with hints and solutions to strengthen your understanding. MERRY MATH - 6 solutions are prepared by Experienced Embibe Experts.