Solve the linear system by graphing. Verify your answers. y = - 1 2 x - 4 and y = 1 3 x + 1

Given equation: y = - 1 2 x - 4 The table of y = - 1 2 x - 4 is shown here: x - 6 - 5 - 4 - 3 - 2 - 1 y = - 1 2 x - 4 - 1 - 3 2 - 2 - 5 2 - 3 - 7 2 The table of y = 1 3 x + 1 is shown here: x - 6 - 5 - 4 - 3 - 2 - 1 y = 1 3 x + 1 - 1 - 2 3 - 1 3 0 1 3 2 3 The graphs are shown here: The intersection of two graphs is - 6 , - 1 Now, if we put x = - 6 in y = - 1 2 x - 4 , we get y = - 1 2 × - 6 - 4 = 3 - 4 = - 1 Similarly, if we put x = - 6 in y = 1 3 x + 1 , we get y = 1 3 - 6 + 1 = - 2 + 1 = - 1 So, the solution is verified.

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MYP Mathematics A concept-based approach 3>Chapter 7 - Linear Systems Social Entrepreneurship>Practice 2

David Weber, Talei Kunkel, Rose Harrison and, Fatima Remtulla Solutions for Chapter: Linear Systems Social Entrepreneurship, Exercise 10: Practice 2

Author:David Weber, Talei Kunkel, Rose Harrison & Fatima Remtulla

David Weber Mathematics Solutions for Exercise - David Weber, Talei Kunkel, Rose Harrison and, Fatima Remtulla Solutions for Chapter: Linear Systems Social Entrepreneurship, Exercise 10: Practice 2

Attempt the practice questions on Chapter 7: Linear Systems Social Entrepreneurship, Exercise 10: Practice 2 with hints and solutions to strengthen your understanding. MYP Mathematics A concept-based approach 3 solutions are prepared by Experienced Embibe Experts.