M. Tyra Solutions for Chapter: Streams, Exercise 1: Exercises

A boat moves upstream at the rate of $1 \mathrm{km}$ in $10 \mathrm{minutes}$ and downstream at the rate of $1 \mathrm{km}$ in $6 \mathrm{minutes}$ . The speed of the current is _____ $\mathrm{km}/\mathrm{hr}$.

A boat covers $24 \mathrm{km}$ upstream and $36 \mathrm{km}$ downstream in $6$ hours, while it covers $36 \mathrm{km}$ upstream and $24 \mathrm{km}$ downstream in $6\frac{1}{2}$ hours. The velocity of the current is _____.

The respective ratio between the time taken by the boat to travel the same distance upstream in stream A and that in stream B is $7:6$. The speed of the boat is $16 \mathrm{km}/\mathrm{h}$ and the speed of stream A is double the speed of stream B. What is the speed of stream B? (in km/h)

A boat takes a total time of twelve hours to travel $105 \mathrm{km}$ upstream and the same distance downstream. The speed of the boat in still water is six times that of the current. What is the speed of the boat in still water? (in $\mathrm{km}/\mathrm{hr}$)

A boat running downstream covers a distance of $30 \mathrm{km}$ in $2$ hours. While coming back the boat takes $6$ hours to cover the same distance. If the speed of the current is half that of the boat, what is the speed of the boat? (in $\mathrm{km}/\mathrm{h}$)

The time taken by a boat to cover a distance of '$\mathrm{D}-56$' $\mathrm{km}$ upstream is half of that taken by it to cover a distance of '$\mathrm{D}$' $\mathrm{km}$ downstream. The ratio of the speed of the boat downstream to that upstream is $5 : 3$. If the time taken to cover '$\mathrm{D}-32$' $\mathrm{km}$ upstream is $4$ hours, what is the speed of water current? (in $\mathrm{km}/\mathrm{h}$)

A boat takes $19$ hours to travel downstream from point A to point B and coming back to a point C midway between A and B. If the speed of the stream is $4 \mathrm{km}/\mathrm{hr}$ and the speed of the boat in still water is $14 \mathrm{km}/\mathrm{hr}$, what is the distance between A and B ?

A boat covers $18 \mathrm{km}$ downstream in $3$ hours. If the speed of the current is $\frac{1}{3}$ of its downstream speed, in what time will it cover a distance of $100 \mathrm{km}$ upstream?