Multiply x 3 9 y 2 by 27 y x 5

We are given to multiply x 3 9 y 2 by 27 y x 5 . The product of two rational expressions is the product of their numerators divided by the product of their denominators and the resulting expression is then reduced to its lowest form. Thus, we have, x 3 9 y 2 × 27 y x 5 = x 3 × 27 y 9 y 2 × x 5 = x × x × x × 3 × 3 × 3 × y 3 × 3 × y × y × x × x × x × x × x = 3 x 2 y . Therefore, the required answer is 3 x 2 y .

Multiply x 4 b 2 x - 1 by x 2 - 1 a 4 b 3 .

We are given to multiply x 4 b 2 x - 1 by x 2 - 1 a 4 b 3 . The product of two rational expressions is the product of their numerators divided by the product of their denominators and the resulting expression is then reduced to its lowest form. Thus, we have, x 4 b 2 x - 1 × x 2 - 1 a 4 b 3 = x 4 × b 2 × x 2 - 1 x - 1 × a 4 × b 3 = x 4 × b 2 x - 1 × x × x × x × x × b × b × ( x + 1 ) ( x - 1 ) a × a × a × a × b × b × b × x - 1 = x 4 ( x - 1 ) a 4 b . [Use a 2 - b 2 = a + b a - b ] Therefore, the required answer is x 4 ( x - 1 ) a 4 b .

E M B I B E

Mathematics Standard 10>Chapter 3 - Algebra>Solved Example

Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 15: Solved Example

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Algebra, Exercise 15: Solved Example

Attempt the free practice questions on Chapter 3: Algebra, Exercise 15: Solved Example with hints and solutions to strengthen your understanding. Mathematics Standard 10 solutions are prepared by Experienced Embibe Experts.