Tamil Nadu Board Solutions for Chapter: Relations and Functions, Exercise 10: Exercise 1.4

A function $f:[-5, 9]\to R$ is defined as follows $f\left(x\right)=\left\{\begin{array}{ll}6x+1& \text{ if }-5\le x<2\\ 5x^2-1& \text{ if }2\le x<6\\ 3x-4& \text{ if }6\le x\le 9\end{array}\right.$. Find $f\left(7\right)-f\left(1\right)$.

A function $f:[-5, 9]\to R$ is defined as $f\left(x\right)=\left\{\begin{array}{ll}6x+1& \text{ if }-5\le x<2\\ 5x^2-1& \text{ if }2\le x<6\\ 3x-4& \text{ if }6\le x\le 9\end{array}\right.$. Find $2f\left(4\right)+f\left(8\right)$.

A function $f:[-5, 9]\to R$ is defined as $f\left(x\right)=\left\{\begin{array}{ll}6x+1& \text{ if }-5\le x<2\\ 5x^2-1& \text{ if }2\le x<6\\ 3x-4& \text{ if }6\le x\le 9\end{array}\right.$. Find $\frac{2f(-2)-f\left(6\right)}{f\left(4\right)+f(-2)}$.

The function $‘t’$ which maps temperature in Celsius $\left(C\right)$ into temperature in Fahrenheit $\left(F\right)$ is defined by $t\left(C\right)=F$ where $F=\frac{9}{5}C+32$. Find $t\left(0\right)$.

The function $‘t’$ which maps temperature in Celsius $\left(C\right)$ into temperature in Fahrenheit $\left(F\right)$ is defined by $t\left(C\right)=F$ where $F=\frac{9}{5}C+32.$ Find $t\left(28\right)$.

The function $‘t’$ which maps temperature in Celsius $\left(C\right)$ into temperature in Fahrenheit $\left(F\right)$ is defined by $t\left(C\right)=F$ where $F=\frac{9}{5}C+32$. Find $t\left(-10\right)$.

The function $‘t’$ which maps temperature in Celsius $\left(C\right)$ into temperature in Fahrenheit $\left(F\right)$ is defined by $t\left(C\right)=F$ where $F=\frac{9}{5}C+32$. If the value of $C =k°$ when $t\left(C\right)=212$, then value of $k$ is

The function $‘t’$ which maps temperature in Celsius $\left(C\right)$ into temperature in Fahrenheit $\left(F\right)$ is defined by $t\left(C\right)=F$ where $F=\frac{9}{5}C+32$.  Find the temperature when the Celsius value is equal to the Fahrenheit value.