Question

Kannan divides a circular disc of radius $14 cm$ into four equal parts. What is the perimeter of a quadrant-shaped disc? (use $π = \frac{22}{7}$ )

Accepted Answer

To find the perimeter of the quadrant disc, we need to find the circumference of quadrant shape.

Given that the radius of the circular disc $(r) = 14 cm$ .

We know that the circumference of circle $= 2 πr$

So, the circumference of the quadrant arc $= \frac{1}{4} \times 2 πr$

$= \frac{πr}{2}$

$= \frac{22}{7} \times \frac{14}{2}$

$= 22 cm$

Given, the radius of the circle $r = 14 cm$

The perimeter of the required quadrant-shaped disc $=$ The circumference of the quadrant arc $+$ Radius of the circular disc $+$ Radius of the circular disc

$= 14 cm + 14 cm + 22 cm$

$= 50 cm$

Hence, the perimeter of the required quadrant-shaped disc is $50 cm$ .

Tamil Nadu Board Solutions for Chapter: Measurements, Exercise 8: Example 2.8

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Measurements, Exercise 8: Example 2.8

Questions from Tamil Nadu Board Solutions for Chapter: Measurements, Exercise 8: Example 2.8 with Hints & Solutions

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