Express sin 74 ∘ in terms of cosine

sin 74 ∘ = sin 90 ∘ - 16 ∘ (since, 90 ∘ - 16 ∘ = 74 ∘ ) RHS is of the form sin 90 ∘ - θ = cos θ Therefore sin 74 ∘ = cos 16 ∘

Express tan 12 ∘ in terms of cotangent

tan 12 ∘ = tan 90 ∘ - 78 ∘ (since 12 ∘ = 90 ∘ - 78 ∘ ) RHS is of the form tan 90 ∘ - θ = cot θ Therefore tan 12 ∘ = cot 78 ∘

Express cosec 39 ∘ in terms of secant

cosec 39 ∘ = cosec 90 ∘ - 51 ∘ (since 39 ∘ = 90 ∘ - 51 ∘ ) RHS is of the form cosec 90 ∘ - θ = sec θ Therefore cosec 39 ∘ = sec 51 ∘

E M B I B E

Mathematics Standard 9>Chapter 6 - Trigonometry>Solved Example

Tamil Nadu Board Solutions for Chapter: Trigonometry, Exercise 7: Solved Example

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Trigonometry, Exercise 7: Solved Example

Attempt the free practice questions on Chapter 6: Trigonometry, Exercise 7: Solved Example with hints and solutions to strengthen your understanding. Mathematics Standard 9 solutions are prepared by Experienced Embibe Experts.

Questions from Tamil Nadu Board Solutions for Chapter: Trigonometry, Exercise 7: Solved Example with Hints & Solutions

EASY

9th Tamil Nadu Board

IMPORTANT

Mathematics Standard 9>Chapter 6 - Trigonometry>Solved Example>Q 7

Express

$\sin 74^{\circ}$ in terms of cosine

EASY

9th Tamil Nadu Board

IMPORTANT

Mathematics Standard 9>Chapter 6 - Trigonometry>Solved Example>Q 7

Express

$\tan 12^{\circ}$ in terms of cotangent

EASY

9th Tamil Nadu Board

IMPORTANT

Mathematics Standard 9>Chapter 6 - Trigonometry>Solved Example>Q 7

Express

$cosec 39^{\circ}$ in terms of secant

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