Draw a frequency polygon to represent the following data : class -- interval 30 - 34 35 - 39 40 - 44 45 - 49 50 - 54 55 - 59 Frequency 12 16 20 8 10 4

The class intervals given are not continuous so, first we will make it continuous by subtracting 0 . 5 from the lower limit of each class interval and adding 0 . 5 to the the upper limit of each class interval. After that we have to find the class marks (mid values) of each interval, that is ( lower limit + upper limit ) 2 . The points of the frequency polygon for each class interval is (class marks, frequency). class - interval 29 . 5 - 34 . 5 34 . 5 - 39 . 5 39 . 5 - 44 . 5 44 . 5 - 49 . 5 49 . 5 - 54 . 5 54 . 5 - 59 . 5 class - marks 32 37 42 47 52 57 frequency 12 16 20 8 10 4

Draw a histogram and frequency poygon in the same graph to represent the following data: class - interval 140 - 145 145 - 150 150 - 155 155 - 160 160 - 165 165 - 170 frequency 25 30 20 15 35 40

The frequency table for the given distribution is- class interval 140 - 145 145 - 150 150 - 155 155 - 160 160 - 165 165 - 170 class - marks 140 + 145 2 = 142 . 5 147 . 5 152 . 5 157 . 5 162 . 5 167 . 5 frequency 25 30 20 15 35 40 The required combined histogram and frequency polygon is shown in the following figure

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Mathematics>Chapter 5 - Statistics>TEST YOUR SKILLS

K C Sisodia Solutions for Chapter: Statistics, Exercise 2: TEST YOUR SKILLS

Author:K C Sisodia

K C Sisodia Mathematics Solutions for Exercise - K C Sisodia Solutions for Chapter: Statistics, Exercise 2: TEST YOUR SKILLS

Attempt the practice questions on Chapter 5: Statistics, Exercise 2: TEST YOUR SKILLS with hints and solutions to strengthen your understanding. Mathematics solutions are prepared by Experienced Embibe Experts.