Solve the following equation by systematic method 1 3 x - 5 2 = 6

Given, 1 3 x - 5 2 = 6 Taking LCM of denominators, ⇒ 2 x - 5 6 = 6 Applying cross multiplication, ⇒ 2 x - 5 = 36 Adding 5 on both sides, ⇒ 2 x - 5 + 5 = 36 + 5 ⇒ 2 x = 41 Divide by 2 on both sides, ⇒ 2 x 2 = 41 2 ⇒ x = 41 2

Solve the following equation by systematic method x 2 + x 3 + x 4 = 13

Given: x 2 + x 3 + x 4 = 13 L C M 2 , 3 , 4 = 12 ⇒ 6 x + 4 x + 3 x 12 = 13 13 12 x = 13 Multiply both sides of the equation by 12 13 , we get ⇒ x = 13 × 12 13 ⇒ x = 12 Therefore, the required answer is 12 .

Solve the following equation by systematic method 3 4 - 5 x 6 = 9 11

Given, 3 4 - 5 x 6 = 9 11 Taking LCM of denominators, ⇒ 3 × 3 12 - 5 x × 2 12 = 9 11 ⇒ 9 - 10 x 12 = 9 11 Apply cross multiplication, ⇒ 11 9 - 10 x = 12 × 9 ⇒ 99 - 110 x = 108 Add 110 x on both sides, ⇒ 99 - 110 x + 110 x = 108 + 110 x ⇒ 110 x + 108 = 99 Subtract 108 on both sides, ⇒ 110 x + 108 - 108 = 99 - 108 ⇒ 110 x = - 9 ⇒ x = - 9 110

Solve the following equation by systematic method 2 3 x - 5 - 1 4 x - 2 = 9 2

Given, 2 3 x - 5 - 1 4 x - 2 = 9 2 ⇒ 2 x - 10 3 - x - 2 4 = 9 2 ⇒ 4 2 x - 10 - 3 x - 2 12 = 9 2 ⇒ 8 x - 40 - 3 x + 6 12 = 9 2 ⇒ 5 x - 34 6 = 9 Apply cross multiplication, ⇒ 5 x - 34 = 54 Add 34 on both sides ⇒ 5 x - 34 + 34 = 54 + 34 ⇒ 5 x = 88 Divide by 5 on both sides ⇒ 5 x 5 = 88 5 ⇒ x = 88 5

Solve the following equation by systematic method 9 x + 7 2 - x - x - 2 7 = 36

Given, 9 x + 7 2 - x - x - 2 7 = 36 ⇒ 9 x + 7 2 - 7 x - x + 2 7 = 36 ⇒ 7 9 x + 7 - 2 6 x + 2 14 = 36 ⇒ 63 x + 49 - 12 x - 4 = 504 ⇒ 51 x + 45 = 504 Subtract 45 on both sides ⇒ 51 x + 45 - 45 = 504 - 45 ⇒ 51 x = 459 Divide by 51 on both sides ⇒ 51 x 51 = 459 51 = 9 ⇒ x = 9

Solve the following equation by systematic method 3 x - 1 3 + 4 x = 8

Given, 3 x - 1 3 + 4 x = 8 3 x - 1 + 12 x 3 = 8 Apply cross multiplication, ⇒ 15 x - 1 = 24 Adding 1 on both sides, ⇒ 15 x - 1 + 1 = 24 + 1 ⇒ 15 x = 25 Divide by 15 on both sides, ⇒ 15 x 15 = 25 15 ⇒ x = 5 3

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Maths Hub (ICSE)>Chapter 7 - Linear Equations in One Variable>Check Point

S Purkayastha Solutions for Chapter: Linear Equations in One Variable, Exercise 2: Check Point

Author:S Purkayastha

S Purkayastha Mathematics Solutions for Exercise - S Purkayastha Solutions for Chapter: Linear Equations in One Variable, Exercise 2: Check Point

Attempt the free practice questions on Chapter 7: Linear Equations in One Variable, Exercise 2: Check Point with hints and solutions to strengthen your understanding. Maths Hub (ICSE) solutions are prepared by Experienced Embibe Experts.