Ramendra C Mukerjee Solutions for Chapter: Problems Based on Equations: Stoichiometry, Exercise 2: Objective Problems

Assuming that petrol is octane $\left({\mathrm{C}}_8{\mathrm{H}}_{18}\right)$ and has a density of $0.8 \mathrm{g} {\mathrm{mL}}^{-1}$, $1.425 \mathrm{litre}$ of petrol on complete combustion will consume.

$12 \mathrm{gram}$ of $\mathrm{Mg}$ will react completely with an acid to give:

$10 \mathrm{mL}$ of gaseous hydrocarbon on combustion, gives $40 \mathrm{mL}$ of ${\mathrm{CO}}_2 \left(\mathrm{g}\right)$ and $50 \mathrm{mL}$ of ${\mathrm{H}}_2\mathrm{O} \left(\mathrm{vapour}\right)$. The hydrocarbon is:

For complete oxidation of $4 \mathrm{litre}$ of $\mathrm{CO}$ at $\mathrm{NTP}$, the required volume of ${\mathrm{O}}_2$ at $\mathrm{NTP}$ is:

The minimum quantity in grams of ${\mathrm{H}}_2\mathrm{S}$ needed to precipitate $63.5 \mathrm{g}$ of ${\mathrm{Cu}}^{2+}$ will be nearly.

If $0.5 \mathrm{mol}$ of ${\mathrm{BaCl}}_2$ is mixed with $0.2 \mathrm{mol}$ of ${\mathrm{Na}}_3{\mathrm{PO}}_4,$ the maximum number of moles of ${\mathrm{Ba}}_3{\left({\mathrm{PO}}_4\right)}_2$ that can be formed is.

For the reaction $\mathrm{A}+2\mathrm{B}\to \mathrm{C}, 5 \mathrm{mol}$ of $\mathrm{A}$ and $8 \mathrm{mol}$ of $\mathrm{B}$ will produce.

A mixture of ${\mathrm{N}}_2$ and ${\mathrm{H}}_2$ reacts in a closed container to form ${\mathrm{NH}}_3$. The reaction ceases before either of the reactants has been totally consumed. At this stage, $2.0 \mathrm{mol}$ each of ${\mathrm{N}}_2, {\mathrm{H}}_2$ and ${\mathrm{NH}}_3$ are present. The moles of ${\mathrm{N}}_2$and ${\mathrm{H}}_2$ present originally were respectively.