NCERT Solutions for Chapter: Areas of Parallelograms and Triangles, Exercise 1: Exercise

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides $8 cm$ and $6 cm$ is:

The area of the Parallelogram $ABCD$ is

If parallelogram $ABCD$ and rectangle $ABEM$ are of equal area, then:

 The mid-point of the sides of a triangle along with any of the vertices as the fourth point make a parallelogram of area equal to

Two parallelograms are on equal bases and between the same parallels. The ratio of their areas is

$ABCD$ is a quadrilateral whose diagonal $AC$ divides it in two parts, equal in area, then quadrilateral $ABCD$ 

If a triangle and a parallelogram are on the same base and between same parallels, then the ratio of the area of the triangle to the area of the parallelogram is

$ABCD$ is a trapezium with parallel sides $AB=a cm$ and $\mathrm{DC}=b \mathrm{cm}$. $E$and $F$ are the midpoints of the non-parallel sides. The ratio of ar $\left(ABFE\right)$ and ar $\left(EFCD\right)$is