NCERT Solutions for Chapter: Electromagnetic Induction, Exercise 1: MCQ

A square of side $L$ meters lies in the x-y plane in a region where the magnetic field is given by $B=B_{\circ } (2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}) \mathrm{T}$, where $B_{\circ }$ is constant. The magnitude of flux passing through the square is

A loop, made of straight edges have six corners at $\mathrm{A}(0,0,0), \mathrm{B}(L,0,0), \mathrm{C}(L\mathit{,}L\mathit{,}0), \mathrm{D}(0,L,0) \mathrm{E}(0,0,L)$ and $F(0,0,L)$. A magnetic field $B=B_{\circ } (\hat{\mathrm{i}}+\hat{\mathrm{k}}) \mathrm{T}$ is present in the region. The flux passing through the loop $\mathrm{ABCDEFA}$ (in that order) is

A cylindrical bar magnet is rotated about its axis (Figure). A wire is connected from the axis and is made to touch the cylindrical surface through a contact. Then 

There are two coils $\mathrm{A}$ and $\mathrm{B}$ as shown in Figure. A current starts flowing in $\mathrm{B}$ as shown, when $\mathrm{A}$ stops moving. The current in $\mathrm{A}$ is counterclockwise. $\mathrm{B}$ is kept stationary when $\mathrm{A}$ moves. We can infer that

Same as problem $4$ except the coil $\mathrm{A}$ is made to rotate about a vertical axis (figure). No current flows in $\mathrm{B}$ if $\mathrm{A}$ is at rest. The current in coil $\mathrm{A}$, when the current in $\mathrm{B}$ (at $t=0$) is counterclockwise and the coil $\mathrm{A}$ is as shown at this instant, $t=0$, is

The self-inductance $\mathrm{L}$. of a solenoid of length $\mathrm{l}$ and area of cross-section $\mathrm{A}$, with a fixed number of turns $\mathrm{N}$ increases as