Evaluate the expressions. Place the letter corresponding to each number to solve the riddle given below. 8 + ( - 2 × 6 ) = ----- = Y 9 × - 5 ( 1 - 2 ) = ----- = L ( - 3 - 9 ) ÷ - 4 = ----- = K ( 42 ÷ 7 ) × 2 - 8 = ----- = U - 2 ( - 3 + 6 ÷ 2 ) = ----- = B 20 - 3 ( 3 + 2 ) = ----- = I ( - 9 + 3 ) ( 8 ÷ - 2 ) = ----- = E 25 - 4 + ( 5 ÷ - 5 ) = ----- = T ( - 4 × 5 ) + ( - 8 ) = ----- = R ( - 18 ÷ - 3 ) × 10 = ----- = O ( 8 × 2 ) + ( 4 × 2 ) = ----- = E 35 - 5 - 7 × 5 = ----- = I 8 × 5 + - 5 × - 1 = ----- = L

We have to evaluate the given expressions. So by using the concept of BODMAS we can simplify the given expression. We know BODMAS stands for Bracket, Of, Division, Multiplication, Addition, and Subtraction. The BODMAS is used to explain the order of operation of a mathematical expression. We have, ⇒ 8 + ( - 2 × 6 ) = 8 + ( - 12 ) = 8 - 12 = - 4 = Y ⇒ 9 × - 5 ( 1 - 2 ) = 9 × - 5 ( - 1 ) = 9 × 5 = 45 = L ⇒ ( - 3 - 9 ) ÷ - 4 = - 12 ÷ - 4 = - 12 - 4 = 3 = K Similarly, we can solve the remaining. Hence, the required solution is, 8 + ( - 2 × 6 ) = - 4 = Y 9 × - 5 ( 1 - 2 ) = 45 = L ( - 3 - 9 ) ÷ - 4 = 3 = K ( 42 ÷ 7 ) × 2 - 8 = 4 = U - 2 ( - 3 + 6 ÷ 2 ) = 0 = B 20 - 3 ( 3 + 2 ) = 5 = I ( - 9 + 3 ) ( 8 ÷ - 2 ) = 24 = E 25 - 4 + ( 5 ÷ - 5 ) = 20 = T ( - 4 × 5 ) + ( - 8 ) = - 28 = R ( - 18 ÷ - 3 ) × 10 = 60 = O ( 8 × 2 ) + ( 4 × 2 ) = 24 = E 35 - 5 - 7 × 5 = - 5 = I 8 × 5 + - 5 × - 1 = 45 = L

E M B I B E

NEW CHALLENGE MATHEMATICS 6>Chapter 11 - Operation BODMAS>Exercise 1

Kusum Shivaram and Pratima Rao Solutions for Chapter: Operation BODMAS, Exercise 1: Exercise 1

Author:Kusum Shivaram & Pratima Rao

Kusum Shivaram Mathematics Solutions for Exercise - Kusum Shivaram and Pratima Rao Solutions for Chapter: Operation BODMAS, Exercise 1: Exercise 1

Attempt the free practice questions on Chapter 11: Operation BODMAS, Exercise 1: Exercise 1 with hints and solutions to strengthen your understanding. NEW CHALLENGE MATHEMATICS 6 solutions are prepared by Experienced Embibe Experts.