Complete the table for an event: Spinning the spinner shown here. Number of Outcomes Possible Outcomes Probability of each Outcome

We can also define the probability by using following formula Probability = Number of successful outcomes Number of possible outcomes In the given problem, the spinner is having four partitions, marked as 1 , 2 , 3 and 4 . So the total number of successful outcomes is 4 . If we spin the spinner for one time, then there are chances that the pointer may stop at 1 or at 2 or at 3 or at 4 . So, the possible outcomes are 1 , 2 , 3 , 4 . The probability of getting 1 is given by 1 4 (using the above formula). Similarly, probability for 2 is 1 4 . Therefore, the probability of each outcome is 1 4 . Hence, required table is Number of Outcomes Possible Outcomes Probability of each Outcome 4 1 , 2 , 3 , 4 1 4

Complete the table for an event: Spinning the spinner shown here. Number of Outcomes Possible Outcomes Probability of each Outcome

We can also define the probability by using following formula Probability = Number of successful outcomes Number of possible outcomes In the given problem, the spinner is having six partitions, marked as 1 , 2 , 3 , 4 , 5 and 6 . So the total number of successful outcomes is 6 . If we spin the spinner for one time, then there are chances that the pointer may stop at 1 or at 2 or at 3 or at 4 or 5 or 6 . So, the possible outcomes are 1 , 2 , 3 , 4 , 5 , 6 . The probability of getting 1 is given by 1 6 (using the above formula). Similarly, probability for 2 is 1 6 And so on. Therefore, the probability of each outcome is 1 6 . Hence, the required table is, Number of Outcomes Possible Outcomes Probability of each Outcome 6 1 , 2 , 3 , 4 , 5 , 6 1 6

Complete the table for an event: Spinning the spinner shown here. Number of Outcomes Possible Outcomes Probability of each Outcome

We can also define the probability by using following formula Probability = Number of successful outcomes Number of possible outcomes In the given, the spinner is having eight partitions, marked as 1 , 2 , 3 , 4 , 5 , 6 , 7 and 8 . So the total number of successful outcomes is 8 . If we spin the spinner for one time, then there are chances that the pointer may stop at 1 or at 2 or at 3 or at 4 or 5 or 6 or 7 or 8 . So, the possible outcomes are 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 . The probability of getting 1 is given by 1 8 (using the above formula). Similarly, probability for 2 is 1 8 And so on. Therefore, the probability of each outcome is 1 8 . Hence, the required table is, Number of Outcomes Possible Outcomes Probability of each Outcome 8 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 1 8

Complete the table for an event: Tossing two coins. Number of Outcomes Possible Outcomes Probability of each Outcome

We can also define the probability by using following formula Probability = Number of successful outcomes Number of possible outcomes When you toss a coin, there are only two possible outcomes. It will land with the head or with the tail up. So, the probability is 1 2 . In the given problem, there are total two coins are tossed, So, the possible outcomes are Head, Head; Head, Tail; Tail, Head; Tail, Tail. Therefore, there are total 4 Possible outcomes. And when we are tossing once, we can get any one of the above combination, so the number of successful outcomes is 1 . Probability of each outcome = 1 4 (using above formula) Hence, the required table is, Number of Outcomes Possible Outcomes Probability of each Outcome 4 HH, HT, TH, TT 1 4

Complete the table for an event: Choosing a letter from the word 'NUMBERS'. Number of Outcomes Possible Outcomes Probability of each Outcome

We can also define the probability by using following formula Probability = Number of successful outcomes Number of possible outcomes In the given problem, the given word is 'NUMBERS', you can observe that there are total seven letters in that word, so when you are picking a letter, you can pick any one of the seven letters. So, there are 7 possible ways of picking a letter. Therefore, there are total 7 Possible outcomes. And when you are supposed to pick a letter, there is possibility that you can pick any one letter, that means the possible outcomes will be all the letters of the word 'NUMBERS'. So, the number of successful outcomes is 1 . Probability of each outcome = 1 7 (using above formula) Hence, the required table is, Number of Outcomes Possible Outcomes Probability of each Outcome 7 All the letters of the word 'NUMBERS' 1 7

Complete the table for an event: Choosing a letter from the consonants of the English Alphabet. Number of Outcomes Possible Outcomes Probability of each Outcome

We can also define the probability by using following formula Probability = Number of successful outcomes Number of possible outcomes We know that in English Alphabet, we had total 26 letters, out of which 5 are vowels and 21 are consonants. Therefore, there are total 21 Possible outcomes. When we are suppose to choose any letter, it can be anyone, out of the 21 consonants. So, the possible outcomes can be all the letters of 21 consonants. And when we are choosing each letter from the consonants, so the number of successful outcomes is 1 . Probability of each outcome = 1 21 (using above formula) Hence, the required table is, Number of Outcomes Possible Outcomes Probability of each Outcome 21 All the consonants 1 21

E M B I B E

New Mathematics Today Class 7>Chapter 25 - Chance and Probability>Worksheet

O P Malhotra, S K Gupta and, Anubhuti Gangal Solutions for Chapter: Chance and Probability, Exercise 2: Worksheet

Author:O P Malhotra, S K Gupta & Anubhuti Gangal

O P Malhotra Mathematics Solutions for Exercise - O P Malhotra, S K Gupta and, Anubhuti Gangal Solutions for Chapter: Chance and Probability, Exercise 2: Worksheet

Attempt the free practice questions on Chapter 25: Chance and Probability, Exercise 2: Worksheet with hints and solutions to strengthen your understanding. New Mathematics Today Class 7 solutions are prepared by Experienced Embibe Experts.