S. L. Arora Solutions for Chapter: Wave Optics, Exercise 5: Problems For Practice

A soap film $5\times {10}^{-5} \mathrm{cm}$ thick is viewed at an angle of $35°$ to the normal. Find the wavelength of light in the visible spectrum which will be absent from reflected light $(\mu =1.33).$ Given wavelength range of the visible spectrum is $3900\mathrm{\AA }$ to $7800\mathrm{\AA }$.

A thin film of thickness $4\times {10}^{-5} \mathrm{cm}$ and $\mu =1.5$ is illuminated by white light incident normal to its surface. What wavelength (expressed in $\mathrm{\AA }$ ) in the visible range be intensified in the reflected beam?

In a thin film, between two points $A$ and $B$, eight fringes are observed with light of wavelength $5461 \mathrm{\AA }$. How many fringes will be observed between the same two points $A$ and $B$ if the wavelength of light used is $6500 \mathrm{\AA }$?

With a thin air film between two points, $6$ fringes appear when light of wavelength $5890 \mathrm{\AA }$ is used. Calculate the difference in the thickness of the film (expressed in $\mathrm{\mu m}$) between the two points.

White light is incident normally on a plane parallel thin film of $\mu =1.5$. Find the minimum thickness of the film in $\mathrm{nm}$ for which light of $\lambda =4000 \mathrm{\AA }$ is absent from the reflected light.

A soap film of refractive index $4/3$ and thickness $1.5\times {10}^{-4}\mathrm{cm}$ is illuminated by white light incident at angle of $45°$. The reflected light is examined by a spectroscope in which a dark band corresponding to the wavelength $5\times {10}^{-5} \mathrm{cm}$ is found. Find the order of the interference band.

White light is incident on a soap film of $\mu =4/3$ at an angle of $30°.$ On examining the transmitted light with a spectrometer, a dark band of wavelength $5.5\times {10}^{-7}\mathrm{m}$ is found. Minimum thickness of the film is $1.11\times {10}^{-\mathrm{n}} \mathrm{m}$. Value of $\mathrm{n}$ is