Editorial Board Solutions for Chapter: Arithmetic Maths, Exercise 1: PROBLEMS ON AGES

The ages of A and B are in the ratio $8 : 5$. If the sum of their ages in $39$ years, what will be the ratio of their ages after $9$ years?

Present ages of A and B are $50$ years and $18$ years respectively. In how many years will A be twice as old as B.

Ratio between present ages of A and B is $3 : 4$. What is the present age of A, if $4$ years ago the ratio was $5 : 7$?

A man is $24$ years older than his son, In two years, his age will be twice the age of his son. The present age of the son is:

The age of father $10$ years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

The sum of the present ages of a father and his son os $60$ years. Six years ago, father's age was five times the age of the son. After $6$ years, son's age will be:

Ramesh was asked to state his age in years. His reply was "Take my age three years hence, multiply it by $3$ and then subtract three times my age three years ago and you will know how old I am". What was the age of the person?

The sum of the ages of $5$ children born at the intervals of $3$ years each is $50$ years. What is the age of the youngest child?