Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 1: Exercise#1

The resistance of a coil is $5$ ohm and a current of $0.2 \mathrm{A}$ is induced in it due to a varying magnetic field. The rate of change of magnetic flux in it will be -

If the length and area of cross-section of an inductor remain same but the number of turns is doubled, its self-inductance will become-

Self-inductance of a solenoid depends on-

When a current flowing in a coil changes from $3 \mathrm{A}$ to $2 \mathrm{A}$ in $1 \mathrm{m} \mathrm{s}$, $5 \mathrm{V}$ emf is induced in it. The self-inductance of the coil will be

In the figure magnetic energy stored in the coil is (in steady state)

The rate of change of current in the inductor initially is

Both the inductors and the cell are ideal. Find the current (in Amperes) $2 \mathrm{H}$ inductance in steady state.

A metallic square wire frame $ABCD$ of side a is moving with a constant velocity $v$ in a uniform magnetic field $B$ as shown. The emf induced between points $A$ and $C$ is :