R.K. Singh Solutions for Chapter: SSC Advanced Maths. : Previous Years Solved Papers, Exercise 21: SSC CGL Tier-I Exam. : 20.07 .2014, 1st

In triangle $\mathrm{ABC}$ a straight line parallel to $\mathrm{BC}$ intersects $\mathrm{AB}$ and $\mathrm{AC}$ at $\mathrm{D}$ and  $\mathrm{E}$ respectively. If $\mathrm{AB}=2 \mathrm{AD}$ then $\mathrm{DE}$ $:$ $\mathrm{BC}$ is-

$\mathrm{ABCD}$ is a rectangle of which $\mathrm{AC}$ is a diagonal. The value of $\left({\tan }^2\angle \mathrm{CAD}+1\right){\sin }^2\angle \mathrm{BAC}$ is-

If $\mathrm{tanx}=\sin 45°·\cos 45°+\sin 30°$ then the value of $\mathrm{x}$ is :

For any real values of $\mathrm{\theta },\sqrt{\frac{\mathrm{sec\theta }-1}{\mathrm{sec\theta }+1}}=?$

If the sum and difference of two angles are $135°$ and $\frac{\mathrm{\pi }}{12}$ respectively, then the value of the angles in degree measure are-

Value of ${\sec }^2\mathrm{\theta }-\frac{{\sin }^2\mathrm{\theta }-2{\sin }^4\mathrm{\theta }}{2{\cos }^4\mathrm{\theta }-{\cos }^2\mathrm{\theta }}$ is:

If $\mathrm{x}=\mathrm{a}(\mathrm{sin\theta }+\mathrm{cos\theta }),\mathrm{y}=\mathrm{b}(\mathrm{sin\theta }-\mathrm{cos\theta })$ then the value of $\frac{{\mathrm{x}}^2}{{\mathrm{a}}^2}+\frac{{\mathrm{y}}^2}{{\mathrm{b}}^2}$ is :

If $\sin 5\mathrm{\theta }=\cos 20°\left(0°<\mathrm{\theta }<90°\right)$ then the value of $\mathrm{\theta }$ is :