Monicaa Abhijit Solutions for Chapter: Mensuration-I (Plane Figures), Exercise 2: EXERCISE 17.2

Find the area of the trapezium whose:

bases$=10 \mathrm{cm}$ and $12 \mathrm{cm}$ and altitude $=5 \mathrm{cm}$

Find the area of a trapezium whose parallel sides are $77 \mathrm{cm}$ and $60 \mathrm{cm}$ and length of non parallel sides are $25 \mathrm{cm}$ and $26 \mathrm{cm}$.

The area of trapezium is $105 {\mathrm{cm}}^2$. If one of the parallel side is $28 \mathrm{cm}$ and the distance between the parallel sides is $5 \mathrm{cm}$, find the length of the other parallel side.

Find the area of the trapezium $\mathrm{PART}$ whose sides $\mathrm{PA}=10 \mathrm{cm}, \mathrm{PT}=\mathrm{AR}=10 \mathrm{cm}$ and $\mathrm{TR}=22 \mathrm{cm}.$ Also $\mathrm{PA}\parallel \mathrm{TR}$.

Top surface of a table is trapezium in shape. Find its area if its parallel sides are $1.5 \mathrm{m}$ and $2 \mathrm{m}$ and the perpendicular distance between them is $1.2 \mathrm{m}$.

Find the area of the given figure.

The ratio of the lengths of parallel sides of a trapezium is $3:5$. The distance between them is $12 \mathrm{cm}$. If the area of the trapezium is $720 {\mathrm{cm}}^2,$ find the lengths of the parallel sides.

Find the area of the given figure.