R S Aggarwal and Veena Aggarwal Solutions for Exercise 5: EXERCISE 3E

Expansion of ${\left(1+\frac{2}{3}a\right)}^3$ is $1+\frac{8}{27}{a}^3+ka+\frac{4}{3}{a}^2$, then find the value of $k.$

If $1+\frac{27}{125}{a}^3+\frac{9a}{5}+\frac{27}{25}{a}^2={\left(1+ka\right)}^3$, find the value of $k$. (write the answer in fraction form)

If $125x^3-27y^3-225x^{2}y+135x{y}^2={\left(kx-my\right)}^3$, find the value of $k+m$.

If $a^3{x}^3-3a^{2}b{x}^2+3a{b}^{2}x-b^3={\left(kx+m\right)}^3$, find $k+m$.

If $\frac{64}{125}{a}^3-\frac{96}{25}{a}^2+\frac{48}{5}a-8={\left(ka-2\right)}^3$, find the value of $k$. (write the answer in fraction form)

If $a^3-12a\left(a-4\right)-64={\left(a+k\right)}^3$, find the value of $k$.

${\left(103\right)}^3=$?

Evaluate

 ${\left(99\right)}^3$