R S Aggarwal and Veena Aggarwal Solutions for Exercise 2: MULTIPLE-CHOICE QUESTIONS (MCQ)

In $∆ABC$, if $\angle A-\angle B=42°$ and $\angle B-\angle C=21°$, then $\angle B=$?

In a $∆ABC$, side $BC$ is produced to $D$. If $\angle ABC=50°$ and $\angle ACD=110°$, then $\angle A=$?

In the given figure, the sides $CB$ and $BA$ of $∆ABC$ have been produced to $D$ and $E$ respectively such that $\angle ABD=110°$ and $\angle CAE=135°$, then $\angle ACB=$?

The sides $BC, CA$ and $AB$ of $∆ABC$ have been produced to $D, E$ and $F$ respectively, then $\angle BAE+\angle CBF+\angle ACD=?$

In the given figure, $EAD\perp BCD$. Ray $FAC$ cuts ray $EAD$ at point $A$such that $\angle EAF=30°$. Also, in $∆BAC$, $\angle BAC=x°$ and $\angle ABC=\left(x+10\right)°$. Then the value of $x$ is:

In the given figure, two rays $BD$ and $CE\hspace{0.17em}$intersect at a point $A$. The side $BC$ of $∆ABC$ have been produced on both sides to points $F$ and $G$ respectively. If $\angle ABF=x°, \angle ACG=y°$ and $\angle DAE=z°$, then $z=$?

In the given figure, lines $AB$ and $CD\hspace{0.17em}$intersect at point $O$. The sides $CA$ and $OB$ have been produced to $E$ and $F$ respectively such that $\angle OAE=x°$ and $\angle DBF=y°$. If $\angle OCA=80°$, $\angle COA=40°$ and $\angle BDO=70°$, then $x°+y°=$?

In the given figure, side $BC$ of $∆ABC$ has been produced to a point $D$. If $\angle A=3y°$, $\angle B=x°$, $\angle C=5y°$ and $\angle ACD=7y°$, then find the value of $x°$.