R S Aggarwal and Veena Aggarwal Solutions for Exercise 4: TEST YOURSELF

In the given figure, $ABCD$ is a quadrilateral in which $\angle ABC=90°,\angle BDC=90°$$,$$AC=17 \mathrm{cm}, BC=15 \mathrm{cm}, BD=12 \mathrm{cm}$ and $CD=9 \mathrm{cm}.$ The area of quad. $ABCD$ is

In the given figure $ABCD$ is a trapezium in which $AB=40 \mathrm{m}, BC=15 \mathrm{m}, CD=28 \mathrm{m}$, $AD=9 \mathrm{m}$ and $CE\perp AB.$ Area of trap. $ABCD$ is 

The sides of a triangle are in the ratio $12:14:25$ and its perimeter is $25.5 \mathrm{cm}$. The largest side of the triangle is

The parallel sides of a trapezium are $9.7 \mathrm{cm}$ and $6.3 \mathrm{cm},$ and the distance between them is $6.5 \mathrm{cm}.$ The area of the trapezium is

The diagonal of a rhombus are $48 \mathrm{cm}$and $20 \mathrm{cm}$. Find the perimeter of the rhombus.

The diagonals of a rhombus are$48 \mathrm{cm}$ and $20 \mathrm{cm}$ long. Find the perimeter of the rhombus.

The adjacent sides of parallelogram are $36 \mathrm{cm}$ and $27 \mathrm{cm}$ in length. If the distance between the shorter sides is $12 \mathrm{cm}$, find the distance between the longer sides.

In a four-sided field, the length of the longer diagonal is $128 \mathrm{m}$. The length of perpendiculars from the opposite vertices upon this diagonal are $22.7 \mathrm{m}$ and $17.3 \mathrm{m}$. Find the area of the field.