The hypotenuse of a right triangle is 1 1 2 metres and another side is 1 2 metre. Calculate its perimeter correct to a centimetre.

Given, hypotenuse = 1 1 2 m = 3 2 m and another side = 1 2 m Let the third side be x m Using the Pythagoras theorem, we get x 2 + 1 2 2 = 3 2 2 ⇒ x 2 = 9 4 - 1 4 = 8 4 = 2 ⇒ x = 2 m Perimeter of a triangle = Sum of it's three sides = 3 2 + 1 2 + 1 . 41 = 3 . 41 m = 3 . 41 × 100 cm = 341 cm

What is the hypotenuse of a right triangle with perpendicular sides 2 centimetres and 3 centimetres? How much more is the sum of the perpendicular sides than the hypotenuse?

Perpendicular sides of a right triangle are 2 cm and 3 cm We need to find the hypotenuse of a right triangle Using Pythagoras theorem, Hypotenuse 2 = 2 2 + 3 2 Hypotenuse 2 = 5 Hypotenuse = 5 cm Sum of the perpendicular sides = 2 + 3 cm Difference between the perpendicular sides and hypotenuse = 5 - 2 + 3 cm

E M B I B E

Standard 9th Mathematics Part - 1>Chapter 2 - NEW NUMBERS>Exercise 2

Exercise 2

Author:Kerala Board

Kerala Board Mathematics Solutions for Exercise 2

Simple step-by-step solutions to Exercise 2 questions of NEW NUMBERS from Standard 9th Mathematics Part - 1. Also get 3D topic explainers, cheat sheets, and unlimited doubts solving on EMBIBE.

Questions from Exercise 2 with Hints & Solutions

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9th kerala board

IMPORTANT

Standard 9th Mathematics Part - 1>Chapter 2 - NEW NUMBERS>Exercise 2>Q 1

The hypotenuse of a right triangle is $1 \frac{1}{2}$ metres and another side is $\frac{1}{2}$ metre. Calculate its perimeter correct to a centimetre.

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9th kerala board

IMPORTANT

Standard 9th Mathematics Part - 1>Chapter 2 - NEW NUMBERS>Exercise 2>Q 4

What is the hypotenuse of a right triangle with perpendicular sides $\sqrt{2}$ centimetres and $\sqrt{3}$ centimetres? How much more is the sum of the perpendicular sides than the hypotenuse?

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