Question

Find the area of an irregular polygon field whose measures are as given in the figure.

Accepted Answer

Given,

The given field has four triangles (I, III, IV and V) and a trapezium (II).

Area of the triangle (I) $= \frac{1}{2} \times b \times h = \frac{1}{2} \times 5 \times 6 = 15 m^{2}$

Area of the trapezium (II) $= \frac{1}{2} h (a + b) = \frac{1}{2} \times 13 \times (6 + 4) = 65 m^{2}$

Area of the triangle (III) $= \frac{1}{2} \times b \times h = \frac{1}{2} \times 8 \times 4 = \frac{32}{2} = 16 m^{2}$

Area of the triangle (IV) $= \frac{1}{2} \times b \times h = \frac{1}{2} \times 13 \times 10 = 65 m^{2}$

Area of the triangle (V) $= \frac{1}{2} \times b \times h = \frac{1}{2} \times 13 \times 10 = 65 m^{2}$

Therefore, the total area of the field $= 15 + 65 + 16 + 65 + 65 = 226 m^{2}$ .

Tamil Nadu Board Solutions for Chapter: Measurements, Exercise 10: Example

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Measurements, Exercise 10: Example

Questions from Tamil Nadu Board Solutions for Chapter: Measurements, Exercise 10: Example with Hints & Solutions

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