Question

Find the rational numbers that should be added and subtracted so that they will make the sum

3 \frac{1}{2} + 1 \frac{3}{4} + 2 \frac{3}{8}

to the nearest whole number.

Accepted Answer

Given,

$3 \frac{1}{2} + 1 \frac{3}{4} + 2 \frac{3}{8}$

We need to simplify, we get

Now,

$3 \frac{1}{2} + 1 \frac{3}{4} + 2 \frac{3}{8} = \frac{7}{2} + \frac{7}{4} + \frac{19}{8}$

$= (\frac{7}{2} \times \frac{4}{4}) + (\frac{7}{4} \times \frac{2}{2}) + (\frac{19}{8} \times \frac{1}{1})$

$= (\frac{28}{8}) + (\frac{14}{8}) + (\frac{19}{8})$

$= \frac{28 + 14 + 19}{8}$

$= \frac{61}{8}$

$= 7 \frac{5}{8}$ , which lies between the whole numbers $7$ and $8$ .

If we subtract $\frac{5}{8}$ from $7 \frac{5}{8}$ , it becomes $7$ . i.e., $(7 \frac{5}{8} - \frac{5}{8}) = (\frac{61}{8} - \frac{5}{8}) = \frac{56}{8} = 7$

If we add $\frac{3}{8}$ to $7 \frac{5}{8}$ , it becomes $7 \frac{5}{8} + \frac{3}{8} = (\frac{61}{8} + \frac{3}{8}) = \frac{64}{8} = 8$ .

Tamil Nadu Board Solutions for Chapter: Numbers, Exercise 19: Example

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Numbers, Exercise 19: Example

Questions from Tamil Nadu Board Solutions for Chapter: Numbers, Exercise 19: Example with Hints & Solutions

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