Solve the following equation and verify the answer. n 5 - 5 = n 6 + 1 2

Given equation is n 5 - 5 = n 6 + 1 2 . Now on transposing the constants to one side, we get ⇒ n 5 - n 6 = 1 2 + 5 ⇒ 6 n - 5 n 30 = 1 + 10 2 ⇒ n 30 = 11 2 ⇒ n = 11 × 30 2 ⇒ n = 11 × 15 ⇒ n = 165 Verification: Substitute n = 165 in n 5 - 5 = n 6 + 1 2 . ⇒ 165 5 - 5 = 165 6 + 1 2 ⇒ 33 - 5 = 27 . 5 + 0 . 5 ⇒ 28 = 28 Therefore, L.H.S = R.H.S. Hence, verified.

Solve the following equation and verify the answer. 2 x 5 – 3 2 = x 2 + 1

Given equation is 2 x 5 – 3 2 = x 2 + 1 . Now on transposing the constants to one side, we get ⇒ 2 x 5 - x 2 = 1 + 3 2 ⇒ 4 x - 5 x 10 = 2 + 3 2 ⇒ - x 10 = 5 2 ⇒ - x = 5 2 × 10 ⇒ - x = 5 × 5 ⇒ x = - 25 Verification: Substitute x = 5 in 2 x 5 – 3 2 = x 2 + 1 . ⇒ 2 ( - 25 ) 5 - 3 2 = - 25 2 + 1 ⇒ - 10 - 3 2 = - 25 2 + 1 ⇒ - 10 - 1 . 5 = - 12 . 5 + 1 ⇒ - 11 . 5 = - 11 . 5 Therefore, L. H. S = R. H. S. Hence, verified.

Solve the following equation and verify the answer. 2 m 3 + 8 = m 2 – 1

Given equation is 2 m 3 + 8 = m 2 – 1 . Now on transposing the constants to one side, we get ⇒ 2 m 3 - m 2 = - 1 - 8 ⇒ 4 m - 3 m 6 = - 9 ⇒ m = - 9 × 6 ⇒ m = - 54 Verification: Substitute m = - 54 in 2 m 3 + 8 = m 2 – 1 . ⇒ 2 ( - 54 ) 3 + 8 = - 54 2 - 1 ⇒ - 36 + 8 = - 27 - 1 ⇒ - 28 = - 28 Therefore, L. H. S = R. H. S. Hence, verified.

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Tryout Maths A book on Mental Maths>Chapter 9 - Linear Equations In One Variable>Exercise

S K Khanuja Solutions for Chapter: Linear Equations In One Variable, Exercise 2: Exercise

Author:S K Khanuja

S K Khanuja Mathematics Solutions for Exercise - S K Khanuja Solutions for Chapter: Linear Equations In One Variable, Exercise 2: Exercise

Attempt the free practice questions on Chapter 9: Linear Equations In One Variable, Exercise 2: Exercise with hints and solutions to strengthen your understanding. Tryout Maths A book on Mental Maths solutions are prepared by Experienced Embibe Experts.