A die is thrown 1000 times with the frequencies of the outcomes 1 , 2 , 3 , 4 , 5 and 6 as given in the following table: Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 Find the probability of getting a number less than 3 .

The given table is, Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 A die is rolled 1000 times. Thus, the total outcomes is = 1000 . Now, let H be the event of getting a number less than 3 . Therefore, the favourable outcomes = 179 + 150 = 329 We know that, P H = g e t t i n g a n u m b e r l e s s t h a n 3 T o t a l o u t c o m e s ⇒ P H = 329 1000 = 0 . 329 Hence, the probability of getting a number less than 3 is 0 . 329 .

A die is thrown 1000 times with the frequencies of the outcomes 1 , 2 , 3 , 4 , 5 and 6 as given in the following table: Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 Find the probability of getting a number greater than 3 .

The given table is, Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 A die is rolled 1000 times. Thus, the total outcomes is = 1000 . Now, let H be the event of getting a number greater than 3 . Therefore, the favourable outcomes = 149 + 175 + 190 = 514 We know that, P H = g e t t i n g a n u m b e r g r e a t e r t h a n 3 T o t a l o u t c o m e s ⇒ P H = 514 1000 = 0 . 514 Hence, the probability of getting a number greater than 3 is 0 . 514 .

A die is thrown 1000 times with the frequencies of the outcomes 1 , 2 , 3 , 4 , 5 and 6 as given in the following table: Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 Find the probability of getting an odd prime number.

The given table is, Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 A die is rolled 1000 times. Thus, the total outcomes is = 1000 . Now, let H be the event of getting an odd prime number. In a die the odd prime numbers are 3 , and 5 Therefore, the favourable outcomes = 157 + 175 = 332 We know that, P H = g e t t i n g a n o d d p r i m e n u m b e r T o t a l o u t c o m e s ⇒ P H = 332 1000 = 0 . 332 Hence, the probability of getting an odd prime number is 0 . 332 .

A die is thrown 1000 times with the frequencies of the outcomes 1 , 2 , 3 , 4 , 5 and 6 as given in the following table: Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 Find the probability of getting a composite number.

The given table is, Outcomes 1 2 3 4 5 6 Frequency 179 150 157 149 175 190 A die is rolled 1000 times. Thus, the total outcomes is = 1000 . Now, let H be the event of getting a composite number. In a die the composite numbers are 4 , and 6 Therefore, the favourable outcomes = 149 + 190 = 339 We know that, P H = g e t t i n g a c o m p o s i t e n u m b e r T o t a l o u t c o m e s ⇒ P H = 339 1000 = 0 . 339 Hence, the probability of getting an odd prime number is 0 . 339 .

On a busy road, following data was observed about cars passing through it and the number of occupants: Number of occupants 1 2 3 4 5 Number of cars 29 26 23 17 5 Find the probability that it has exactly 5 occupants.

The given table is, Number of occupants 1 2 3 4 5 Number of cars 29 26 23 17 5 The total outcomes = 29 + 26 + 23 + 17 + 5 = 100 Let H be the event of getting exactly 5 occupants. We know that, P H = N u m b e r o f g e t t i n g e x a c t l y 5 o c c u p a n t s T o t a l o u t c o m e s Therefore, P H = 5 100 ⇒ 5 ÷ 5 100 ÷ 5 = 1 20 Hence, the probability of getting exactly 5 occupants are 1 20 .

On a busy road, following data was observed about cars passing through it and the number of occupants: Number of occupants 1 2 3 4 5 Number of cars 29 26 23 17 5 Find the probability that it has atleast 3 occupants.

The given table is, Number of occupants 1 2 3 4 5 Number of cars 29 26 23 17 5 The total outcomes = 29 + 26 + 23 + 17 + 5 = 100 Let H be the event of getting atleast 3 occupants. So, the favourable outcomes = 23 + 17 + 5 = 45 We know that, P H = N u m b e r o f g e t t i n g a t l e a s t 3 o c c u p a n t s T o t a l o u t c o m e s Therefore, P H = 45 100 ⇒ 45 ÷ 5 100 ÷ 5 = 9 20 Hence, the probability of getting exactly 5 occupants are 9 20 .

EASY

9th CBSE

IMPORTANT

Earn 100

$1500$ families with $2$ children were selected randomly, and the following data were recorded.

Number of girls in a family $0$ $1$ $2$

Number of families $211$ $814$ $475$

Find the probability of a family, chosen at random having no boys.

Important Questions on Probability

EASY

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 5

$1500$ families with $2$ children were selected randomly, and the following data were recorded.

Number of girls in a family	$0$	$1$	$2$
Number of families	$211$	$814$	$475$

Find the probability of a family, chosen at random having atleast one girl.

EASY

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 5

$1500$ families with $2$ children were selected randomly, and the following data were recorded.

Number of girls in a family	$0$	$1$	$2$
Number of families	$211$	$814$	$475$

Find the probability of a family, chosen at random having no girl.

MEDIUM

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 6

A die is thrown $1000$ times with the frequencies of the outcomes $1, 2, 3, 4, 5$ and $6$ as given in the following table:

Outcomes	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$179$	$150$	$157$	$149$	$175$	$190$

Find the probability of getting a number less than $3$ .

MEDIUM

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 6

A die is thrown $1000$ times with the frequencies of the outcomes $1, 2, 3, 4, 5$ and $6$ as given in the following table:

Outcomes	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$179$	$150$	$157$	$149$	$175$	$190$

Find the probability of getting a number greater than $3$ .

MEDIUM

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 6

A die is thrown $1000$ times with the frequencies of the outcomes $1, 2, 3, 4, 5$ and $6$ as given in the following table:

Outcomes	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$179$	$150$	$157$	$149$	$175$	$190$

Find the probability of getting an odd prime number.

MEDIUM

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 6

A die is thrown $1000$ times with the frequencies of the outcomes $1, 2, 3, 4, 5$ and $6$ as given in the following table:

Outcomes	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$179$	$150$	$157$	$149$	$175$	$190$

Find the probability of getting a composite number.

MEDIUM

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 7

On a busy road, following data was observed about cars passing through it and the number of occupants:

Number of occupants	$1$	$2$	$3$	$4$	$5$
Number of cars	$29$	$26$	$23$	$17$	$5$

Find the probability that it has exactly $5$ occupants.

MEDIUM

9th CBSE

IMPORTANT

CBSE Syllabus Standard Mathematics for Class IX>Chapter 15 - Probability>Exercise 15>Q 7

On a busy road, following data was observed about cars passing through it and the number of occupants:

Number of occupants	$1$	$2$	$3$	$4$	$5$
Number of cars	$29$	$26$	$23$	$17$	$5$

Find the probability that it has atleast $3$ occupants.

1500 families with 2 children were selected randomly, and the following data were recorded. Number of girls in a family 0 1 2 Number of families 211 814 475 Find the probability of a family, chosen at random having no boys.

Important Questions on Probability

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$1500$ families with $2$ children were selected randomly, and the following data were recorded.

Number of girls in a family $0$ $1$ $2$

Number of families $211$ $814$ $475$

Find the probability of a family, chosen at random having no boys.