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A force F=(i^-2j^+5k^) N is acting at a point r=(2i^+j^+3k^) m. Find torque about the origin.

Important Questions on Rotational Mechanics

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The density of a rod AB increases continuously from A to B. Is it easier to set it in rotation by clamping it at A and applying a perpendicular force at B or by clamping it at B and applying the force at A? Explain your answer.
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A uniform disc of radius 20 cm and mass 2 kg can rotate about a fixed axis through the centre and perpendicular to its plane. A massless cord is round along the rim of the disc. If a uniform force of 2 newtons is applied on the cord, tangential acceleration of a point on the rim of the disc will be
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A door 1.6 m wide requires a minimum force of 1 N to be applied at the free end to open or close it. The minimum force that is required at a point 0.4 m away from the hinges for opening or closing the door is
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Four equal and parallel forces are acting on a rod (as shown in figure at distances of 20 cm, 40 cm, 60 cm and 80 cm respectively from one end of the rod. Under the influence of these forces the rod
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A weightless rod is acted on by upward parallel forces of 2 N and 4 N at ends A and B, respectively. The total length of the rod is AB=3 m. To keep the rod in equilibrium, a force of 6 N should act in the following manner:
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The figure shows a uniform disc, with mass M=2.4 kg and radius R=20 cm, mounted on a fixed horizontal axle. A block of mass m=1.2 kg hangs from a massless cord that is wrapped around the rim of the disc. The tension in the cord is:

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A thin uniform stick of length l and mass m is held horizontally with its end B hinged on the edge of a table. The point A is suddenly released. The acceleration of the centre of mass of the stick at the time of release is:

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If the earth is a point mass of 6×1024 kg revolving around the sun at a distance of 1.5×108 km and in time, of T=3.14×107 seconds, then the angular momentum of the earth around the sun is: